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3 years ago

What do the planets Saturn, Neptune, and Uranus have in common?

Physics

1 answer:

NemiM [27]3 years ago

5 0

Answer:

they are all outer planets

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10. During 4th period we put Klaudia in a box because she was talking too much. We still heard her voice through the box so we d

Alex787 [66]

Answer: Mr. Whitmore would need 7 or more students ( 7.17) to make the box start moving and go outside

Explanation:

Given that;

friction force of ground box = 68 N

student of 7th grade = n

Whitmore can apply a force of 25 N

every other 7th grade student can apply a force of 6 N.

now

friction force = forced applied by whitmore + total force ny 7th grade student

we substitute

68 = 25 + 6n

6n = 68 - 25

6n = 43

n = 43/6

n = 7.17

Therefore Mr. Whitmore would need 7 or more students ( 7.17) to make the box start moving and go outside

6 0

3 years ago

The plank is 5.1 meters long and has a mass of 9.2 kg, ack has a mass of 93.6 kg, and Diane has a mass of 64.2 kg. Assuming Dian

kodGreya [7K]

Answer:

The answer is 0.8 m

Explanation:

According the attached diagram, if we take the momentum in the point 0:

$\frac{m_{D}*5.1 }{2} =m_{J} *X$

Where

mD = mass of Diane = 64.2 kg

mJ = mass of Jack = 93.6 kg

Replacing:

$X=\frac{\frac{64.2*5.1}{2} }{93.6} =1.75m$

$\frac{L}{2} -X=Y=\frac{5.1}{2} -1.75\\Y=0.8m$

8 0

3 years ago

Please help. Having a hard time figuring out

Goryan [66]

Yeah that’s is correct

5 0

3 years ago

What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc

vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, $\rho=2300\ \Omega-m$

Length of rod, l = 20 cm = 0.2 m

Voltage, $V=1\times 10^3\ V$

The resistivity of the rod is given by :

$R=\rho\dfrac{L}{A}$

$R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}$

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

$I=\dfrac{V}{R}$

$I=\dfrac{10^3\ V}{893692.30\ \Omega}$

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

6 0

3 years ago

What causes the formation of ocean currents?

aliina [53]

Ocean currents can be generated by wind, density differences in watermasses caused by temperature and salinity variations, gravity, and events such as earthquakes

5 0

3 years ago