All categories

4 years ago

A cup falls off of a table from a height of 0.75 m. What is the impact speed of the cup?

Physics

2 answers:

Artemon [7]4 years ago

3 0

3.83 meters per second.

andrew-mc [135]4 years ago

3 0

Answer:

The impact speed of the cup is 3.83 m/s.

Explanation:

Given that,

Height = 0.75 m

We need to calculate the impact speed of the cup

Using kinetic and potential energy

$K.E=P.E$

$\dfrac{1}{2}mv^2=mgh$

Where,

M = mass of the cup

v = velocity of cup

g = acceleration due to gravity

h = height

Put the value into the formula

$\dfrac{1}{2}v^2=gh$

$v=\sqrt{2gh}$

$v=\sqrt{2\times9.8\times0.75}$

$v=3.83\ m/s$

Hence, The impact speed of the cup is 3.83 m/s.

You might be interested in

The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of 13.1

ahrayia [7]

Answer:

The temperature is $T = 168.44 \ K$

Explanation:

From the question ewe are told that

The rate of heat transferred is $P = 13.1 \ W$

The surface area is $A = 1.55 \ m^2$

The emissivity of its surface is $e = 0.287$

Generally, the rate of heat transfer is mathematically represented as

$H = A e \sigma T^{4}$

=> $T = \sqrt[4]{\frac{P}{e* \sigma } }$

where $\sigma$ is the Boltzmann constant with value $\sigma = 5.67*10^{-8} \ W\cdot m^{-2} \cdot K^{-4}.$

substituting value

$T = \sqrt[4]{\frac{13.1}{ 0.287* 5.67 *10^{-8} } }$

$T = 168.44 \ K$

7 0

4 years ago

Which is the force of repulsion between two positively-charged particles?

klio [65]

answer>>>>electric force <<<<by the way i don't like physics but i answer this for you ^-^

This is because centripetal force is just the net force of a circular motion. There are no attractive or repulsive forces here. This is not the case here. 
The gravitational force is a force reliant on mass and attraction of the masses. There are attractive forces here, but not really repulsive forces. 
The electric force is the only one that would make sense because it has to do with a relationship between charges and includes both repulsive and attractive forces.

4 0

3 years ago

Read 2 more answers

C2H4O2 is what ??????

alukav5142 [94]

Did you try looking it up ?

8 0

3 years ago

Acceleration is measured in_________ m g m/s m/s2

Nana76 [90]

Acceleration is measured in m/s².

Answer: m/s²

4 0

4 years ago

A ball rolls down the hill which has a vertical height of 15 m. Ignoring friction what would be the gravitational potential ener

trasher [3.6K]

a) Potential energy: 147 m [J]

The gravitational potential energy of an object is given by

$U=mgh$

where

m is its mass

$g=9.8 m/s^2$ is the acceleration of gravity

h is the height of the object above the ground

In this problem,

h = 15 m

We call 'm' the mass of the ball, since we don't know it

So, the potential energy of the ball at the top of the hill is

$U=(m)(9.8)(15)=147 m$ (J)

b) Velocity of the ball at the bottom of the hill: 17.1 m/s

According to the law of conservation of energy, in absence of friction all the potential energy of the ball is converted into kinetic energy as the ball reaches the bottom of the hill. Therefore we can write:

$U=K=\frac{1}{2}mv^2$

where

v is the final velocity of the ball

We know from part a) that

U = 147 m

Substituting into the equation above,

$147 m = \frac{1}{2}mv^2$

And re-arranging for v, we find the velocity:

$v=\sqrt{2\cdot 147}=17.1 m/s$

5 0

3 years ago