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Dima020 [189]
2 years ago
9

As the atomic number of elements within Group 2 increases, the metallic character of each successive element

Chemistry
1 answer:
butalik [34]2 years ago
5 0
Answer: (2), increases

Explanation: Metals are substances which readily loose electrons.
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How many moles in 44.7 kg of carbon dioxide
slava [35]

Answer:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

Explanation:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

7 0
2 years ago
1.
marin [14]
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4 0
3 years ago
Convert 8.876 × 10^12 m^2 to units of km^2.
Darya [45]

Answer:

8.876\times 10^{18}\ km^2

Explanation:

In this problem, we need to convert 8.876 \times 10^{12}\ m^2 to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2

So, 8.876 \times 10^{12}\ m^2 is equal to 8.876\times 10^{18}\ km^2.

7 0
3 years ago
Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to
Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

P_{2} =\frac{T_{2} P_{1} }{T_{1} }

P_{2}=\frac{(337K)(0.55atm)}{418K}

P₂=0.44 atm

8 0
4 years ago
Consider the heating curve. In which region are most particles moving the fastest?
Nikitich [7]

The particles are moving fastest in Region D) 5.

As temperature increases, so does the average kinetic energy (speed) of the molecules.

5 0
3 years ago
Read 2 more answers
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