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gladu [14]
3 years ago
11

Identify the nuclide produced when plutonium-239 decays by alpha emission: 239 94pu→42he + ? express your answer as an isotope u

sing prescripts. 235 92u submithintsmy answersgive upreview part incorrect; try again; 4 attempts remaining part b identify the nuclide produced when thorium-234 decays by beta emission: 234 90th→ 0−1e + ? express your answer as an isotope using prescripts. submithintsmy answersgive upreview part part c identify the nuclide produced when fluorine-18 decays by positron emission: 18 9f→01e + ? express your answer as an isotope using prescripts. submithintsmy answersgive upreview part part d identify the nuclide produced when thallium-201 decays by electron capture: 201 81tl+ 0−1e→00γ + ? express your answer as an isotope using prescripts.
Chemistry
1 answer:
Galina-37 [17]3 years ago
6 0

1. Answer is ₉₂²³⁵U<span>

<span>Since this is an alpha emission the atomic number of the daughter nucleus decreases by 2 while mass number decreases by 4 compared to parent atom. Since parent atom has 94 as atomic number the daughter atom should have </span>94 - 2 = 92 as atomic number<span> <span>and </span></span>239 - 4 = 235 as mass number. <span>

</span></span>₉₄²³⁹Pu → ₂⁴He + ₉₂²³⁵U<span>

2. </span><span>Answer is </span>₉₁²³⁴Pa<span>

</span><span>Since this is a beta emission, a neutron is converted into a proton while emitting an electron. Hence atomic number increases by 1 compared to mass number but mass number remains as same. Hence, the </span>atomic number of the daughter atom<span> <span>should be </span></span>90 + 1 = 91<span> <span>which belongs to </span></span>Pa<span>. But the </span>mass number is same as 234.<span>

</span>₉₀²³⁴Th → ₋₁⁰e + ₉₁²³⁴Pa<span>
</span><span>
3.<span> <span>Answer is </span></span></span>₈¹⁸O<span>

</span><span>Since this is a positron emission, a proton is converted into a neutron while emitting an positron. Hence atomic number decreases by 1 compared to mass number but mass number remains as same. Hence, the </span>atomic number of the daughter atom<span> should be </span>9- 1 = 8 <span>which belong to </span>O<span>. But the </span>mass number is same as 18.<span>

</span>₉¹⁸F → ₊₁⁰e + ₈¹⁸O<span>

4. </span>Answer is ₈₀²⁰¹Hg<span>

</span><span>This is an </span><span>electron capture decay. </span>A<span> proton is converted into a neutron by emitting a gamma ray. In this process </span>mass number remains as same<span> <span>as parent atom which is </span></span>201<span>, but the </span>atomic number is decreased by 1<span> <span>than parent atom. Hence atomic number of daughter nucleus is 81 -1 = </span></span>80 <span>which belongs to </span>Hg.<span>
</span><span>
</span>₈₁²⁰¹Tl +  ₋₁⁰e →  ₀⁰γ + ₈₀<span>²⁰¹Hg</span>

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Answer the following questions: On a 10-fold dilution of a weak acid, the pH will ______________ . On a 10-fold dilution of a we
Scorpion4ik [409]

Answer:

i) increase

ii) decrease

iii) remain the same

iv) No, because it dissociates completely.

Explanation:

On a 10-fold dilution of a weak acid, the pH will increase because the concentration of hydrogen ions will decrease thereby increasing the pH to close to that of water.

On a 10-fold dilution of a weak base, the pH will decrease due to the removal of hydroxide ions from the solution. This results in the solution having a H closer to that of water.

If one adds a very small amount of strong base to a buffered solution, the pH will remain constant because a buffer solution acts to withstand any change to its pH on the addition of small quantities of either an acid or a base.

A buffer solution cannot be made with a strong acid because thy undergo complete dissociation. Therefore, any small addition of base or acid will result in very large changes in the pH of the solution. A buffer solution is made with a weak acid and its conjugate base or a weak base and its conjugate acid.

6 0
3 years ago
A sample of water is cooled from 45°C to 25°C
juin [17]

Answer:

1000 g

Explanation:

Given data:

Initial temperature of water = 45°C

Final temperature of water = 25°C

Heat released = 20 cal (4184×20 = 83680 j)

Mass of water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.184 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25°C - 45°C

ΔT = -20°C

83680 j = m × 4.184 j/g.°C ×20°C

83680 j = m × 83.68 j/g

m = 83680 j / 83.68 j/g

m = 1000 g

5 0
3 years ago
What is the volume of the toy car that has a density of 3 g/mL and a mass of 75 g.
muminat

Answer:

The volume of car having density 3 g/mL and mass 75 g is 25 mL.

Explanation:

Given data:

Volume of car = ?

Density of car = 3 g/mL

Mass of car = 75 g

Solution:

The given problem will be solved through density formula.

Density:

Density is equal to the mass of substance divided by its volume.

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula.

3 g/mL = 75 g/ v

v = 75 g/ 3 g/mL

v = 25 mL

The volume of car having density 3 g/mL and mass 75 g is 25 mL.

7 0
3 years ago
Predict whether the reaction will take place Ag+NaNO3 → AgNO3+Na
atroni [7]
The correct answer would be NO
4 0
3 years ago
Butane gas is used as the fuel in disposable lighters. It burn in oxygen to form carbon dioxide gas and water vapor. What mass o
777dan777 [17]

Answer:

mass of carbon dioxide produced = 87.9153846154 g   ≈  87.92 g

Explanation:

The chemical equation is as follow

Butane = C4H10

oxygen = O2

carbon dioxide = CO2

water = H2O

C4H10 + O2 →  CO2 +  H2O

The equation should be balanced before solving it.

2C4H10 + 13O2 →  8CO2 +  10H2O

molar mass of 13 mole of oxygen = 416 g

molar mass of 8 mole of carbon dioxide = 256 + 96 = 352 g

416 g of oxygen was needed to produce 352 g of carbon dioxide

103.9 g will produce  ?

cross multiply

mass of carbon dioxide produced = 103.9 × 352/416

mass of carbon dioxide produced = 103.9 × 352/416

mass of carbon dioxide produced = 36572.8 /416

mass of carbon dioxide produced = 87.9153846154 g ≈  87.92 g

5 0
3 years ago
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