Answer:
i) increase
ii) decrease
iii) remain the same
iv) No, because it dissociates completely.
Explanation:
On a 10-fold dilution of a weak acid, the pH will increase because the concentration of hydrogen ions will decrease thereby increasing the pH to close to that of water.
On a 10-fold dilution of a weak base, the pH will decrease due to the removal of hydroxide ions from the solution. This results in the solution having a H closer to that of water.
If one adds a very small amount of strong base to a buffered solution, the pH will remain constant because a buffer solution acts to withstand any change to its pH on the addition of small quantities of either an acid or a base.
A buffer solution cannot be made with a strong acid because thy undergo complete dissociation. Therefore, any small addition of base or acid will result in very large changes in the pH of the solution. A buffer solution is made with a weak acid and its conjugate base or a weak base and its conjugate acid.
Answer:
1000 g
Explanation:
Given data:
Initial temperature of water = 45°C
Final temperature of water = 25°C
Heat released = 20 cal (4184×20 = 83680 j)
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.184 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25°C - 45°C
ΔT = -20°C
83680 j = m × 4.184 j/g.°C ×20°C
83680 j = m × 83.68 j/g
m = 83680 j / 83.68 j/g
m = 1000 g
Answer:
The volume of car having density 3 g/mL and mass 75 g is 25 mL.
Explanation:
Given data:
Volume of car = ?
Density of car = 3 g/mL
Mass of car = 75 g
Solution:
The given problem will be solved through density formula.
Density:
Density is equal to the mass of substance divided by its volume.
Formula:
D=m/v
D= density
m=mass
V=volume
Now we will put the values in formula.
3 g/mL = 75 g/ v
v = 75 g/ 3 g/mL
v = 25 mL
The volume of car having density 3 g/mL and mass 75 g is 25 mL.
The correct answer would be NO
Answer:
mass of carbon dioxide produced = 87.9153846154 g ≈ 87.92 g
Explanation:
The chemical equation is as follow
Butane = C4H10
oxygen = O2
carbon dioxide = CO2
water = H2O
C4H10 + O2 → CO2 + H2O
The equation should be balanced before solving it.
2C4H10 + 13O2 → 8CO2 + 10H2O
molar mass of 13 mole of oxygen = 416 g
molar mass of 8 mole of carbon dioxide = 256 + 96 = 352 g
416 g of oxygen was needed to produce 352 g of carbon dioxide
103.9 g will produce ?
cross multiply
mass of carbon dioxide produced = 103.9 × 352/416
mass of carbon dioxide produced = 103.9 × 352/416
mass of carbon dioxide produced = 36572.8
/416
mass of carbon dioxide produced = 87.9153846154 g ≈ 87.92 g