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Doss [256]
3 years ago
12

A rectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t in the y-z plane that make

s an angle of 30o with the y-axis. what is the flux through the loop.
Physics
1 answer:
nalin [4]3 years ago
4 0

area vector of the loop is given by

A = 0.08 * 0.03 (k)

area vector is always perpendicular to the plane of the loop

A = 24 * 10^{-4} (k)

now the magnetic field vector is given as

B = 4.5 (cos30 (j) + sin30 (k))[\tex][tex]B = 3.89 j + 2.25 k

now the magnetic flux is given by

\phi = B. A[\tex][tex]\phi = (3.89 j + 2.25 k ).(24 * 10^{-4} k)

\phi = 5.4 * 10^{-3} Wb

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