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Doss [256]
3 years ago
12

A rectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t in the y-z plane that make

s an angle of 30o with the y-axis. what is the flux through the loop.
Physics
1 answer:
nalin [4]3 years ago
4 0

area vector of the loop is given by

A = 0.08 * 0.03 (k)

area vector is always perpendicular to the plane of the loop

A = 24 * 10^{-4} (k)

now the magnetic field vector is given as

B = 4.5 (cos30 (j) + sin30 (k))[\tex][tex]B = 3.89 j + 2.25 k

now the magnetic flux is given by

\phi = B. A[\tex][tex]\phi = (3.89 j + 2.25 k ).(24 * 10^{-4} k)

\phi = 5.4 * 10^{-3} Wb

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А)
Anastaziya [24]

Answer:

4.5s

Explanation:

u=30m/s

v=50m/s

s=180m

a=constant(given)

By third equation of motion,    v  

2

=u  

2

+2as

(50)  

2

=(30)  

2

+2a(180)

a=  

3

40

​  

m/s  

2

 

By first equation of motion,    v=u+at

50=30+(  

9

40

​  

)t

t=  

2

9

​  

=4.5sec

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Two vectors are presented as a=3.0i +5.0j and b=2.0i+4.0j find (a) a x b, ab (c) (a+b)b and (d) the component of a along the dir
Svet_ta [14]
Let's ask this question step by step:
 Part A) 
 a x b = (3.0i + 5.0j) x (2.0i + 4.0j) = (12-10) k = 2k
 ab = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
 Part (c)
 (a + b) b = [(3.0i + 5.0j) + (2.0i + 4.0j)]. (2.0i + 4.0j)
 (a + b) b = (5.0i + 9.0j). (2.0i + 4.0j)
 (a + b) b = 10 + 36
 (a + b) b = 46
 Part (d)
 comp (ba) = (a.b) / lbl
 a.b = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
 lbl = root ((2.0) ^ 2 + (4.0) ^ 2) = root (20)
 comp (ba) = 26 / root (20)
 answer
 2k
 26
 46
 26 / root (20)
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