A rectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t in the y-z plane that make
s an angle of 30o with the y-axis. what is the flux through the loop.
1 answer:
area vector of the loop is given by

area vector is always perpendicular to the plane of the loop

now the magnetic field vector is given as
![B = 4.5 (cos30 (j) + sin30 (k))[\tex][tex]B = 3.89 j + 2.25 k](https://tex.z-dn.net/?f=B%20%3D%204.5%20%28cos30%20%28j%29%20%2B%20sin30%20%28k%29%29%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%5Btex%5DB%20%3D%203.89%20j%20%2B%202.25%20k)
now the magnetic flux is given by
![\phi = B. A[\tex][tex]\phi = (3.89 j + 2.25 k ).(24 * 10^{-4} k)](https://tex.z-dn.net/?f=%5Cphi%20%3D%20B.%20A%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cphi%20%3D%20%283.89%20j%20%2B%202.25%20k%20%29.%2824%20%2A%2010%5E%7B-4%7D%20k%29)

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Explanation:
Given:
v₀ = 0 m/s
a = 2.50 m/s²
t = 4 s
Find: v
v = at + v₀
v = (2.50 m/s²) (4 s) + 0 m/s
v = 10 m/s
The answer is b no problem
ok i know what your talking about
I believe the correct answer is 40 cm.
initial momentum of 2 kg blob is given as

here we have



initial momentum of 3 kg blob is given as

here we have



So initially 2 kg Blob has most momentum before they collide