Question

A rectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t in the y-z plane that makes an angle of 30o with the y-axis. what is the flux through the loop.

Answer 1

area vector of the loop is given by

$A = 0.08 * 0.03 (k)$

area vector is always perpendicular to the plane of the loop

$A = 24 * 10^{-4} (k)$

now the magnetic field vector is given as

$B = 4.5 (cos30 (j) + sin30 (k))[\tex][tex]B = 3.89 j + 2.25 k$

now the magnetic flux is given by

$\phi = B. A[\tex][tex]\phi = (3.89 j + 2.25 k ).(24 * 10^{-4} k)$

$\phi = 5.4 * 10^{-3} Wb$