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postnew [5]
1 year ago
8

In need of some help with this question please~

Chemistry
1 answer:
NeTakaya1 year ago
5 0

Answer:

5.60 Liters at STP

Explanation:

First you need the balanced reaction equation

2 H2 +  O2   ====>   2  H2O

4 g of oxygen ( O<u>2</u> )  is   4/(15.999*2) moles of O2     (using periodic table)

  Twice the number of moles of H2O re produced   (from equation)

     at STP the volume of a mole of gas is 22.4 liter/ mole

       put all of this together  

         2 *   4 / (15.999*2) moles * 22.4 L/mole = 5.60 L

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Answer:

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Explanation:

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<em>2P₂ + 5O₂ ⇄ 2P₂O₅. </em>

It is clear that 2 mol of P₂ react with <em>5 mol of O₂ </em>to produce <em>2 mol of P₂O₅.</em>

  • Firstly, we need to calculate the no. of moles of 6.92 kilograms of P₂O₅ produced through the reaction:

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<u><em>Using cross multiplication:</em></u>

5 mol of O₂ is needed to produce → 2 mol of P₂O₅, from stichiometry.

??? mol of O₂ is needed to produce → 24.38 mol of P₂O₅.

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where, P is the pressure of the gas in atm (P = 606.1 mm Hg/760 = 0.8 atm).

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R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (396.90°C + 273 = 669.9 K).

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