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KATRIN_1 [288]
3 years ago
8

How many grams of water will form when 10.54g of h2o react with 95.10g of O2

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0
You have to divide them by each other


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In which group on the periodic table does the atom pictures belong?
Triss [41]

Answer: Group 14

Explanation:

It's a carbon atom with 4 valance electrons.

4 0
3 years ago
Read 2 more answers
The hydroboration of an alkene occurs in ___________ which places the boron of the borane on the ___________ carbon of the doubl
Nana76 [90]

Answer: The hydroboration of an alkene occurs in TWO CONCERTED STEP which places the boron of the borane on the LESS SUBSTITUTED carbon of the double bond. The oxidizing agent then acts as a nucleophile, attacking the electrophilic BORON and resulting in the placement of a hydroxyl group on the attached carbon. Thus, the major product of the hydroboration oxidation reaction DOES NOT follow Markovnikov's rule.

Explanation:

Hydroboration is defined as the process which allows boron to attain the octet structure. This involves a two steps pathway which leads to the production of alcohol.

--> The first step: this involves the initiation of the addittion of borane to the alkene and this proceeds as a concerted reaction because bond breaking and bond formation occurs at the same time.

--> The second step: this involves the addition of boron which DOES NOT follow Markovnikov's rule( that is, Anti Markovnikov addition of Boron). This is so because the boron adds to the less substituted carbon of the alkene, which then places the hydrogen on the more substituted carbon.

Note: The Markovnikov rule in organic chemistry states that in alkene addition reactions, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms bonded to it, while the electron-deficient component adds to the carbon atom with more hydrogen atoms bonded to it.

8 0
3 years ago
Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

                         6                          O                       6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

                            x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

4 0
3 years ago
Insert the values from the question above for x, y, z, & n into KxFey(C204)z nH20 anod provide the correct coefficients to b
vlada-n [284]

Answer:

Explanation:

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8 0
2 years ago
In what way does the arrangement of the periodic table tell you information about the elements
Rashid [163]
It gives you the amount of shells, electrons, the type of group it’s one for example: metalloids. The protons and neutrons in that group.
6 0
3 years ago
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