How many grams of water will form when 10.54g of h2o react with 95.10g of O2
1 answer:
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<u>Answer:</u> The final volume of the oxygen gas is 4.04 L
<u>Explanation:</u>
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Hence, the final volume of the oxygen gas is 4.04 L
Are produced 72 grams of water in this reaction.
<h3>Mole calculation</h3>To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:
Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:
So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O
Finally, just find the number of grams of water using your molar mass:
So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
Answer:- An empirical formula of adrenaline is .
Solution:- Convert given percentages to moles and then calculate the mol ratio to get the simplest whole number ratio of moles of atoms which is the empirical formula of the compound.
= 4.725 mol
= 6.56 mol
= 1.773 mol
= 0.591 mol
let's calculate the mol ratio now. To calculate the mole ratio, we divide the moles of each by moleso f N as it's the least one:
= 8
= 11
= 3
= 1
So, an empirical formula of adrenaline is .