1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AleksandrR [38]
3 years ago
10

4 physical properties of spoonfull of sugar

Chemistry
2 answers:
kirill [66]3 years ago
6 0
Um, shiny, metal, grainy, white, silver, small
almond37 [142]3 years ago
3 0
Small crystals 
<span>white, brown </span>
<span>hard as in solid at room temp </span>
<span>sweet </span>
You might be interested in
Heat moves from what source by convection and radiation?
Alona [7]

Answer:

heat can move from any source but if we are being legitimate it moves from convection

Explanation:

8 0
3 years ago
The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit
jok3333 [9.3K]

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0
2 years ago
2H2S + 3O2 → 2SO2 + 2H2O<br><br><br>1. For every 10.0 g of H2S how many moles of SO2 are formed?
Veseljchak [2.6K]

Answer:10

Explanation:

7 0
2 years ago
Free pts *el nose boopo uwu tak a share and hav sum fun
mixas84 [53]
What i don’t get what u mean at all
4 0
2 years ago
Read 2 more answers
Other questions:
  • Magnesium reacts with oxygen to form two compounds. Compound A contains 7.88 g of magnesium for every 15.68 g of oxygen. Compoun
    7·1 answer
  • What strategies did you use when you played the balancing chemical equations game? Which atoms were the easiest to start examini
    9·2 answers
  • What is the consecration of a solution that is made by diluting 50.0 mL of a 40.0 M NaCl solution to a final volume of 1000.0 mL
    12·1 answer
  • By making several measurements with the same balance, a chemist obtained values of 5.224 g, 5.235 g, and 5.259 g for the mass of
    15·1 answer
  • How can you remove energy from matter?
    9·1 answer
  • A forensic scientist reports that a dead woman had high concentrations of a pain-fighting drug in her blood. What type of analys
    7·2 answers
  • Refer to the example about diatomic gases A and B in the text to do problems 19 - 27. How many grams in 3 moles of A2?
    7·2 answers
  • Which of the following remains would be most likely only be found as a compression fossil?
    14·2 answers
  • If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?
    10·1 answer
  • The electron-domain geometry of a sulfur-centered compound is trigonal bipyramidal. The hybridization of the central sulfur atom
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!