Answer:
The radius of the gold nucleus is 7.1x10⁻¹⁵m
Explanation:
The nearest distance is:
(eq. 1)
Where
z = atomic number of gold = 79
e = electron charge = 1.6x10⁻¹⁹C
k = electrostatic constant = 9x10⁹Nm²C²
energy of the particle = 32 MeV = 5.12x10⁻¹²J
At the potential energy is zero, all the energy will be kinetic energy:
Where
m = 4 mp = mass of proton
Replacing in equation 1
They will mix with air. Air consists mostly of nitrogen and oxygen but there are also traces of CO2 and noble gases in air, and helium is one of those noble gases.
Answer:
Mechanical energy is the sum of kinetic and potential energy of a system
(a) What is
the potential energy: PE = -G * M * m/r
Where: M is the mass of the earth which is 5.98 * 10^24 kg.
m is the mass of the satellite.
r is the space from the center of the earth to the satellite
To conclude this distance add the radius of the earth to the
altitude. Radius of the earth is 6.38 * 10^6 meters.
r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6
PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 =
4.71240095 * 10^9 J
(b) magnitude of the gravitational force exerted by the
Earth
Fg = G * M * m/r^2
Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 =
562.3078873 N
(c) There are no other forces that the satellite exert on
the Earth. So therefore, it is 0.
The distance d₁ it rises from rest while the engine is burning is given by
d₁ = d₀ + v₀t + (1/2)at²
d₁ = 0 + 0 + (1/2)·(29.4 m/s²)·(3.98 s)² = 232.85 m
So it gets to 232.85 m and then runs out of fuel. Its velocity v₁ at this point is given by
v₁ = v₀ + at = (29.4 m/s²)·(3.98 s) = 117 m/s
At this point, gravity begins to slow it down until it reaches its peak where its velocity v₂ is zero.
v₂² = v₁² + 2ad₂
where d₂ is the distance it rises until v=0
Since gravity is decelerating the rocket, a = -g, and we have
0² = (117 m/s)² + 2(-9.8 m/s²)d₂
0 = (117)² - (19.6)·d₂
0 = 13,689 - (19.6)·d₂
d₂ = 13,689/19.6 = 698.42 m
So the total height it rises is given by
d₁ + d₂ = 232.85 m + 698.42 m
= 931.27 m
