This diagram shows a ball rolling from left to right along a frictionless

Physics

1 answer:

yanalaym [24]3 years ago

5 0

I’d say C: 1,3,4 because when you think about it section 2 and five would be balanced right?

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13. For an object to appear transparent, what interaction must occur between light waves and the object they hit?

Svetlanka [38]

Answer:

The answer is B

Explanation:

The absorption happens when photons from light hit atoms and molecules, and they vibrate because of that specific interaction. Then the heat ejects from the object in the format of thermal energy.

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3 years ago

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A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7 N. What is the acceleration of the box?

Marysya12 [62]

Answer:

F=ma

a=F/m=9.7N/5.5Kg=1.8 m/s^2

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Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.30 kg and is initially moving to t

snow_lady [41]

Answer:

a) 3.632 m/s

b) 0.462 m/s

Explanation:

Using the law of conservation of momentum:

$m_{1} u_{1} + m_{2} u_{2}= m_{1} V_{1} + m_{2} V_{2}$ ..........(1)

$m_{1} = 0.30 kg\\u_{1} = 2.4 m/s\\m_{2} = 0.80 kg\\u_{2} = 0 m/s$

Substituting the above values into equation (1) and make V2 the subject of the formula:

$0.3(2.4) + 0.80(0)= 0.3 V_{1} + 0.8 V_{2}\\$

$V_{2} = \frac{0.72 - 0.3 V_{1}}{0.8}$ ..................(2)

Using the law of conservation of kinetic energy:

$0.5m_{1} u_{1} ^{2} + 1.2 = 0.5m_{1} V_{1} ^{2} + 0.5m_{2} V_{2} ^{2}\\0.5(0.3) (2.4) ^{2} + 1.2 = 0.5(0.3) V_{1} ^{2} + 0.5(0.8)V_{2} ^{2}\\$

$2.064 = 0.15 V_{1} ^{2} + 0.4V_{2} ^{2}$ .......(3)

Substitute equation (2) into equation (3)

$2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.72 - 0.3V_{1} }{0.8}) ^{2}\\2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.5184 - 0.432V_{1} + 0.09V_{1} ^{2} }{0.64}) \\1.32096 = 0.096 V_{1} ^{2} + 0.20736 - 0.1728V_{1} + 0.036V_{1} ^{2} \\0.132 V_{1} ^{2} - 0.1728V_{1} - 1.1136 = 0\\V_{1} = 3.632 m/s$