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Fed [463]
3 years ago
11

What's is the biggest dog

Physics
2 answers:
lesantik [10]3 years ago
8 0
The largest dog breed is in fact the Great Dane. They are very big but are friendly,patient, and very dependable. 
sergij07 [2.7K]3 years ago
7 0

Answer:

Explanation:

The biggest dog in the world is the Great Dane

The largest dog breed by the American Kennel Club

I hope it'll help you much

Thank you for asking

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A merry-go-round rotates at the rate of
Dimas [21]

So, the new angular speed when the man walks to a point 0 m from the center (in rad/s) is approximately <u>0.87π rad/</u>s.

<h3>Introduction</h3>

Hi ! I will help you with this problem. This problem will mostly adopt the principle of rotational dynamics, especially angular momentum. When there is a change in the mass or radius of rotation of an object, it will not affect its angular momentum, only its angular velocity will change. Therefore, the law of conservation of angular momentum can be written as :

\sf{L_1 = L_2}

\sf{I_1 \times \omega_1 = I_2 \times \omega_2}

\boxed{\sf{\bold{m_1 \times (r_1)^2 \times \omega_1 = m_2 \times (r_2)^2 \times \omega_2}}}

With the following condition :

  • \sf{m_1} = initial mass (kg)
  • \sf{m_2} = final object mass (kg)
  • \sf{r_1} = initial turning radius (m)
  • \sf{r_2} = final turning radius (m)
  • \sf{\omega_1} = initial angular velocity (rad/s)
  • \sf{\omega_2} = final angular velocity (rad/s)

<h3>Rationale</h3>

Previously, we assumed that when rotating, only merry-go-round that experienced inertia so the man will only add to the mass of the merry-go-round. Perhaps, having a man at the end of it will change the slope (direction of torque), but not change the value of angular momentum. So, when this person is in the middle or on the central axis (read: 0 m from the center), the man no longer had any effect on the weight gain.

<h3>Problem Solving</h3>

We know that :

  • \sf{m_1} = initial mass = 88 (man) + 75 (object) = 163 kg
  • \sf{m_2} = final object mass = 75 kg
  • \sf{r_1} = \sf{r_2} = r >> The radius of rotation is always the same
  • \sf{\omega_1} = initial angular velocity = 0.2 rev/s = 0.2 × 2π rad/s >> 0.4π rad/s

What was asked :

  • \sf{\omega_2} = final angular velocity = ... rad/s

Step by step :

\sf{m_1 \times (r_1)^2 \times \omega_1 = m_2 \times (r_2)^2 \times \omega_2}

\sf{163 \times \cancel{(r)^2} \times 0.4 \pi = 75 \times \cancel{(r)^2} \times \omega_2}

\sf{65.2 \pi = 75 \times \omega_2}

\sf{\omega_2 = \frac{65.2 \pi}{75}}

\boxed{\sf{\omega_2 \approx 0.87 \pi \: rad/s}}

<h3>Conclusion</h3>

So, the new angular speed when the man walks to a point 0 m from the center (in rad/s) is approximately 0.87π rad/s

7 0
3 years ago
If the tension in a rope is increased, what will happen to the speed of a wave traveling through the rope?
Lena [83]
"The speed will increase" is the one among the following choices given in the question that describes the speed of a wave traveling through the rope, if <span>the tension in a rope is increased. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that has come to your help.</span>
5 0
3 years ago
Read 2 more answers
A car speed off around a bend at a constant 10m/s explain why it's velocity is not constant
VARVARA [1.3K]
It's velocity is not constant as direction is changing.
 
We know, velocity is speed with direction, so if direction is changing, velocity can't be constant, doesn't matter that speed is constant.

Hope this helps!
8 0
3 years ago
The distance between a speaker and a listener is 8.0 m. Determine the frequency of the sound wave if exactly 20 waves are formed
dmitriy555 [2]

The frequency of the wave is 6800 Hz

<u>Explanation:</u>

Given:

Wave number, n = 20

Speed of light, v = 340 m/s

Frequency, f = ?

we know:

wave number = \frac{frequency}{speed of light}

20 = \frac{f}{340 m/s} \\\\f = 20 X 340 s^-^1\\\\f = 6800 Hz

Therefore, the frequency of the wave is 6800 Hz

4 0
3 years ago
Can someone help me with this question
Anna71 [15]

Answer:

Ionic- Ion

Covalent- Molecules

Explanation:

7 0
2 years ago
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