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Fed [463]
3 years ago
11

What's is the biggest dog

Physics
2 answers:
lesantik [10]3 years ago
8 0
The largest dog breed is in fact the Great Dane. They are very big but are friendly,patient, and very dependable. 
sergij07 [2.7K]3 years ago
7 0

Answer:

Explanation:

The biggest dog in the world is the Great Dane

The largest dog breed by the American Kennel Club

I hope it'll help you much

Thank you for asking

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g A car is traveling east at 15.0 m/s when it turns due north and accelerates to 30.0 m/s, all during a time of 5.00 s. Calculat
nirvana33 [79]

Answer:

from \: first \: equation \: of \: motion \\ v = u + at \\ a =  \frac{v - u}{t}  \\ a =  \frac{30 - 15}{5}  \\ a = 3 {ms}^{ - 2}

3 0
3 years ago
A 80 kg bungee jumper is on a bridge that is 100 meters above a river. Attached to the jumper is a bungee cord that is 50 meters
Usimov [2.4K]

Answer:

a) 70,560 J

b) 88.2 N/m

Explanation:

The spring potential will equal the change in gravity potential

PS = PE = mgh = 80(9.8)(100 - 10) = 70,560 J

PS = ½kx²

k = 2PS/x² = 2(70560)/(100 - 50 - 10)² = 88.2 N/m

7 0
3 years ago
What is the current through resistor #1? (must include unit - A)
Vlad1618 [11]

Answer: 3A

Explanation:

First, we must calculate voltage by summing the reciprocal of the resistances in the circuit

1/40 +1/40 = 2/40 = 1/20 = 1/R, so R = 20Ω

Using Ohm's Law, I = V/R, so the current I is I = 120/20 = 6A

Using Kerchoff's Circuit Law, we know that current will split evenly at a junction, so each resistor will get one half, or 3A.

7 0
3 years ago
A 41-turn square coil of area 0.074 m2 and a 123-turn circular coil are both placed perpendicular to the same changing magnetic
vesna_86 [32]

Answer:

<h3>The area of second coil is ≅ 0.025 m^{2}</h3>

Explanation:

Given :

No. of turns in the first coil N_{1} = 41

No. of turns in the second coil N_{2}  = 123

Area of first coil A_{1} = 0.074 m^{2}

According to the law of electromagnetic induction,

Induced emf = -N \frac{d \phi}{dt}

Where \phi = magnetic flux.

Since given in question emf of both coil is same so we compare above equation.

    -\frac{N_{1} d\phi _{1}   }{dt_{1} }  = -\frac{N_{2} d\phi _{2}   }{dt_{2} }

   \frac{N_{1} A_{1}   dB_{1}  }{dt_{1} }  = \frac{N_{2} A_{2} dB_{2}     }{dt_{2} }

        A_{2} = \frac{N_{1} A_{1}  }{N _{2}  }

        A_{2} = \frac{41 \times 0.074 }{123  }

        A_{2} = 0.0246 = 0.025 m^{2}

Therefore, the area of second coil is ≅ 0.025 m^{2}

4 0
4 years ago
HELP ASAP!!!!!!!!!<br><br><br> What is the difference between a contact force and a distance force?
Karo-lina-s [1.5K]
A contact force are forces that require actual contact (touch) of two pieces of matter.

Distant force is a force that works at a distance not needing any contact (touch) at all.
6 0
3 years ago
Read 2 more answers
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