Answer:
infrared, visible and ultraviolet regions.
Explanation:
Answer:
(c) 0.77 m/s^2 directed 35° south of west.
Explanation:
Let's first find the resultant force and its direction:
F = 20.808 N
To find the direction, we can just imagine the forces as lengths of a right angled triangle.
So, Force (west) will be our perpendicular.
and Force (south) will be our base.
Calculating the angle we have:
Theta = 54.78° (angle from south)
Direction of resultant force = 90 - 54.78 = 35.22° (south of west)
Taking out the acceleration, we get:
F = m * a
20.808 = 27 * a
a = 0.77 m/s^2
So the answer is (c)
Answer:
Explanation:
frequency of radiation
= 8.54 x 10¹⁴
wave length = 3 x 10⁸ / 8.54 x 10¹⁴
= .3513 x 10⁻⁶ m
= 3513 A
Energy of this wave OR energy of each photon in eV
= 12375 / 3513
= 3.52 eV
the minimum amount of energy required = 3.52 eV.
Answer:
The tension in the rod as the ball moves through the bottom circle is 9.8 N
Explanation:
When the ball is released from rest, the centripetal force equals the weight of the ball. So mv²/r = mg where m = mass of ball = 0.5 kg, v = speed of ball, r = radius of vertical circle = length of rod = 0.5 m and g = acceleration due to gravity = 9.8 m/s²
v = √gr = √9.8 m/s² × 0.5 m = √4.9 = 2.21 m/s
Now at the bottom of the circle T - mg = mv²/r where T = tension in the rod
T = m(g + v²/r)
= m(g + (√gr)²/r)
= m(g+ gr/r)
= m(g + g)
= 2mg
= 2 × 0.5 kg × 9.8 m/s²
= 9.8 N
So, the tension in the rod as the ball moves through the bottom circle is 9.8 N
2-slit pattern, slit spacing d, mth bright fringe: sinθ m = mλ d
Fringe position on screen at distance L: ym = L tanθ m ≅ L m( ) λ d
ym = 1.10m( ) 2λ 0.000040m → λ = ( ) 0.042m
0.000040m / 2⎡ ⋅( ) 1.10m ⎣ ⎤⎦ = 7.63×10−7 m
NOTE:tan and sin will be small angles