Answer:
r = -11.6 cm
Explanation:
As we know that the position of center of mass is given as
now we know that three masses are on the left while two are on the right
position of left most mass with respect to the center of the rod is given as
Now we will have
Answer:
v = 2 v₁ v₂ / (v₁ + v₂)
Explanation:
The body travels the first half of the distance with velocity v₁. The time it takes is:
t₁ = (d/2) / v₁
t₁ = d / (2v₁)
Similarly, the body travels the second half with velocity v₂, so the time is:
t₂ = (d/2) / v₂
t₂ = d / (2v₂)
The average velocity is the total displacement over total time:
v = d / t
v = d / (t₁ + t₂)
v = d / (d / (2v₁) + d / (2v₂))
v = d / (d/2 (1/v₁ + 1/v₂))
v = 2 / (1/v₁ + 1/v₂)
v = 2 / ((v₁ + v₂) / (v₁ v₂))
v = 2 v₁ v₂ / (v₁ + v₂)
The question is incomplete but still I answer to assume your thinking.
The picture is attached below!.
Here,
F is the force with which you pull up the incline.
N is the normal force.
w is the weight acting downward.
Axis are mentioned in the attached picture.
Concept:You can see there is no movement of object in the y-direction that means acceleration is zero in y-direction, sum of all the forces in y-direction equal to zero.
According to newton second law,
<span>∑ F = ma
</span>As, acceleration is zero in y-direction, so right hand side is zero in the above equation.
<span>∑ F = 0</span>
N-wcosθ=0
N= m*g*cos25°
N= m*(9.8)*(0.9063)
N= 8.8817*mBy putting the value of mass(m)(not given in the question) you will get the answer.
Hopefully, this is the answer of your question.
They attract each other with force
F=q1*q2/(4πεr^2), where
q1=2.4 µC, q2=4.2 µC,
r=4.9·10-2 m, ε=8.854·10^(-12) SI units.
♦ F=2.4·10-6 * 4.2·10-6 /(4*pi* 8.854·10^(-12) *0.049^2)=
=37.73 N;