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natima [27]
2 years ago
9

A) What volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution?

Chemistry
1 answer:
azamat2 years ago
4 0

Answer:

A.0.51L

B 1.67L

Explanation:

using the formula ;C1V1 =C2V2

15.8×V1=2×4

15.8V1=8

V1=8/15.8

V1=0.51L

apply the same method for B

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2.50 L of a gas at standard temperature and pressure is compressed to 575 mL. What is the new pressure of the gas
vfiekz [6]

Answer:

4.35 atm

Explanation:

According to the information given;

  • Initial volume of the gas, V₁ is 2.50 L
  • Initial pressure of the gas is standard pressure P₁, normally 1 atm
  • New volume of the gas, V₂ is 575 mL

We are required to determine the new pressure of the gas, P₂ ;

To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.

According to Boyle's law;

P₁V₁ = P₂V₂

Therefore, to determine the new pressure, P₂, we rearrange the formula;

New pressure, P₂ = P₁V₁ ÷ V₂

Thus;

P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L

    = 4.3478 atm

     = 4.35 atm

Therefore, the new pressure of the gas is 4.35 atm

6 0
3 years ago
Read 2 more answers
How many joules are required to convert 16.5 g g of ice at 0.0 ∘C ∘ C to liquid water at 32.0 ∘C ∘ C ? The heat of fusion of wat
photoshop1234 [79]

Answer:

5511 J

Explanation:

Applying,

Q = Cm.................... Equation 1

Where Q = amount of heat required to convert ice, C = Heat of fusion of water, m = mass of ice

From the question,

Given: C = 334 J/g, m = 16.5 g

Substitute these values into equation 2

Q = 334(16.5)

Q = 5511 J

Hence, the amount of heat required is 5511 J

4 0
3 years ago
Use the reading below to answer the question.
True [87]

Answer: I think it is amount of rainfall

Explanation:

8 0
3 years ago
Read 2 more answers
Carbon-14 emits beta radiation and decays with a half life of 5730 years. Assume you start with 2.5x10^15 grams of Carbon-14, ho
saveliy_v [14]

The amount remaining at the end of 5 half-lives is 7.81×10¹³ g

From the question given above, the following data were obtained:

  • Half-life (t½) = 5730 years
  • Original amount (N₀) = 2.5×10¹⁵ g
  • Number of half-lives (n) = 5
  • Amount remaining (N) =?

The amount remaining can be obtained as follow:

N = 1/2ⁿ × N₀

N = 1/2⁵ × 2.5×10¹⁵

N = 1/32 × 2.5×10¹⁵

N = 0.03125 × 2.5×10¹⁵

N = 7.81×10¹³ g

Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g

Learn more about half-life: brainly.com/question/25783920

3 0
2 years ago
An object has a mass of 20 g and displaces a volume of 5 mL. What is the object's density?
lara [203]

Hey There!:

The density is the quotient between the mass of a material and the volume occupied by it, The density can be expressed for a substance or for a mixture of substances. For example, water density in ambient conditions is equal to 1.00 g/cm3, which means that in 1 cm³ or 1 mL, there are 1.0 g of water. Therefore:

D = m / V

D = 20 g / 5 mL

D = 4,0 g/mL

hope that helps!


5 0
3 years ago
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