Answer:
<u>4</u>H₂O(l) →<u> 4</u>H₂(g) + <u>2</u>O₂(g)
Balancing equations
1. 3Fe(s) + 4H₂O(g) → Fe₃0₄(s) + 4H₂(g)
2. 2AlBr₃(aq) + 3Cl₂(g) → 2AlCl₃(aq) + 3Br₂(l)
3. 2HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)
4. 2Al(s) + 3Pb(NO₃)₂ → 2Al(NO₃)₃(aq) + 3Pb(s)
5. 3NaOH(aq) + Fe(NO₃)₃ → Fe(OH)₃(s) + 3NaNO₃(aq)
Explanation:
From the question given, I have been able to balance the chemical equations correctly.
In balancing chemical equations, the chemical equation must have equal number of atoms for each element that are both in the reactant side and in the product side.
For the above to be achieved, the number of atoms in each element will have to be multiplied and added.
A look at the balanced chemical equation above, you will discover that each element has the same number of atoms both in the reactant side and in the product side.
I can help you with part 1
Answer:
0.159 \%
Explanation:
The acid will dissociate according to the reaction shown below:-
Given that, pH=3.8
The concentration of can be determined from the expression fo pH as:-
pH = - log
3.8 = - log
=
The initial concentration of RCOOH was 0.10 M, then the percent dissociation was- calculated as shown below:-