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fenix001 [56]
2 years ago
5

Consider the following reaction: 2CH3OH ---> 2CH4+O2 delta H= +252.8kJ. Calculate the amount of heat transferred when 22.0g o

f CH3OH(g) is decomposed by this reaction at constant pressure. Include units
Chemistry
1 answer:
nydimaria [60]2 years ago
4 0
To calculate the amount of heat transferred when an amount of reactant is decomposed, we must look at the balanced reaction and its corresponding heat of reaction. In this case, we can see that 252.8 kJ of heat is transferred per 2 moles of CH3OH used. When 22 g of CH3OH is used, 86.9 kJ is absorbed. 
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__________ could be the formula of an alkene. a. c3h8 b. c2h8 c. c6h6 d. c3h6 e. c17h36
drek231 [11]

The general formula for alkenes is CnH2n, the formula with hydrogen count double the carbon count should be the correct formula for alkene and that is d. C3H6.

What are alkenes?

Alkenes, commonly known as olefins, are organic unsaturated hydrocarbons that have one or more carbon-carbon double bonds in their chemical structure and are composed of carbon and hydrogen atoms.

Alkenes are unsaturated hydrocarbons with a double bond between the carbon atoms. Carbon atoms are connected by at least one double bond. The general formula for alkenes is C n H 2n. Olefin is frequently substituted with alkenes. The word "olefin" comes from the Greek phrase "olefin gas," which denotes the production of oil.

<u>Since, their general formula is CnH2n, the formula with hydrogen count double the carbon count should be the correct formula for alkene and that is d. C3H6.</u>

To learn more about alkenes from the given link below,

brainly.com/question/27179090

#SPJ4

6 0
1 year ago
To what volume would you need to dilute 200 mL of a 5.85M solution of Ca(OH)2 to make it a 1.95M solution?
Blizzard [7]

Answer: 600 mL

Explanation:

Given that;

M₁ = 5.85 m

M₂ = 1.95 m

V₁ = 200 mL

V₂ = ?

Now from the dilution law;

M₁V₁ = M₂V₂

so we substitute

5.85 × 200 = 1.95 × V₂

1170 = 1.95V₂

V₂ = 1170 / 1.95

V₂ = 600 mL

Therefore final volume is 600 mL

8 0
3 years ago
If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
yawa3891 [41]

The pH of the monoprotic weak acid is 2.79.

<h3>What are weak acids?</h3>

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

c (monoprotic acid) = 0.33 M.

Ka = 1.2·10⁻⁶

[A⁻] = [H⁺] = x

[HA] = 0.33 M - x

Ka = [A⁻]·[H⁺] / [HA]

2. 6 × 10⁻⁶ = x² / (0.33 M - x)

Solve quadratic equation: [H⁺] = 0.000524 M.

pH = -log[H⁺]

pH = -log(0.000524 M)

pH = 2.79

Thus,  the pH of the monoprotic weak acid is 2.79

To learn more about weak acids, refer to the below link:

brainly.com/question/13032224

#SPJ4

5 0
2 years ago
Process by which plants, algae, and many types of bacteria use sunlight, water, and carbon dioxide to make food and oxygen
Katena32 [7]

Answer: Photosynthesis

Explanation:

<em>The process of photosynthesis</em> is used to help make food for plants. The inputs are sunlight, water (H2O), and carbon dioxide (CO2). Then the outputs are glucose (C6H12O6) which is food, and oxygen (O2) is released.

I hope this helps :)

4 0
2 years ago
If excess ammonium sulfate reacts with 20.0g of calcium hydroxide how many grams of ammonia are produced
bagirrra123 [75]
The reaction between ammonium sulfate and calcium hydroxide is given below. 
            (NH₄)₂SO₄ + Ca(OH)₂ --> 2NH₃ + CaSO₄ + 2H₂O
From the balance equation, we can conclude that every 74 g of calcium sulfate reacted with enough amount of ammonium sulfate will yield 34 grams of ammonia. From the given amount,
               (20 g calcium sulfate) x (34 grams ammonia / 74 g calcium sulfate)
                               = <em>9.19 g ammonia</em>
3 0
3 years ago
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