Answer:
The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.
0.01 cubic meters
Hope this helps
For the purpose we will here use the ideal gas law:
p×V=n×R×T
V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is universal gas constant, and its value is 8.314 J/mol×K
Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL
Answer: D.
Answer:
D.
Explanation:
I just got it right in the test :)