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grin007 [14]
2 years ago
5

Biomes are defined by specific characteristics. What characteristics would define the biome shown? a. cool and windy with coarse

gravelly soil b. low-growing shrubs and large furry carnivores c. cool and windy with small nocturnal carnivores d. hot and dry with low-growing shrubs

Chemistry
2 answers:
KIM [24]2 years ago
4 0

Answer : Option D) Hot and dry with low growing shrubs.

Explanation : According to the attached image of the Biome, this particular biome displays the hot and dry climatic region along with low growing shrubs. A biomes are the way to divide the largely occurring flora and fauna in a particular place on the Earth's surface. These divisions are made on the basis of climatic patterns, soil types, and the animals and plants that are found to inhabit in that area.

Degger [83]2 years ago
3 0
I think the answer for this question is D.
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Why do solids not diffuse​
Ulleksa [173]

Answer:

This is because of diffusion , the movement of particles from an area of high concentration to an area of low concentration. ... This means that diffusion does not happen in solids – the particles in a solid can only vibrate and cannot move from place to place.

8 0
2 years ago
Read 2 more answers
The isomerization of methyl isonitrile, CH3NC, to acetonitrile, CH3CN, was studied in the gas phase at 215oC, and the following
Viefleur [7K]

Answer:

2.75 × 10⁻⁶ M/s

1.69 × 10⁻⁶ M/s

9.23 × 10⁻⁻⁷ M/s

4.43 × 10⁻⁻⁷ M/s

2.1 × 10⁻⁻⁷ M/s

Explanation:

We have the following information for the isomerization of methyl isonitrile

Time (s)      [CH₃NC] (M)

  0              0.0165

2000          0.0110

5000          0.00591

8000          0.00314

12000         0.00137

15000         0.00074

To calculate the average rate of reaction (r) for each interval, we need to use the following expression:

r = -Δ[CH₃NC]/Δt

Interval 0-2000 s

r = - (0.0110 M-0.0165 M)/2000 s - 0 s = 2.75 × 10⁻⁶ M/s

Interval 2000-5000 s

r = - (0.00591 M-0.0110 M)/5000 s - 2000 s = 1.69 × 10⁻⁶ M/s

Interval 5000-8000 s

r = - (0.00314 M-0.00591 M)/8000 s - 5000 s = 9.23 × 10⁻⁻⁷ M/s

Interval 8000-12000 s

r = - (0.00137 M - 0.00314 M)/12000 s - 8000 s = 4.43 × 10⁻⁻⁷ M/s

Interval 12000-15000 s

r = - (0.00074 M - 0.00137 M)/15000 s - 12000 s = 2.1 × 10⁻⁻⁷ M/s

3 0
2 years ago
Suppose that 25,0 mL of a gas at 725 mmHg and 298K is converted to
posledela

The new volume : 21.85 ml

<h3>Further explanation</h3>

Given

V1=25,0 ml

P1=725 mmHg

T1=298K is converted to

T2=273'K

P2=760 mmHg atm

Required

V2

Solution

Combined gas law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

V2=(P1.V1.T2)/(P2.T1)

V2=(725 x 25 ml x 273)/(760 x 298)

V2=21.85 ml

5 0
2 years ago
As the particles of a solid undergo sublimation , they?
vladimir2022 [97]
They are particular solids.
4 0
3 years ago
Determine whether a gas sample was composed of hydrogen or oxygen.
Nuetrik [128]
The test for this is fairly simple.
We take a glowing match or splint near the gas sample, if the glow intensifies, oxygen is present. 
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5 0
3 years ago
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