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Novay_Z [31]
2 years ago
10

Salim wants to survey the students at his middle school about how much time they spend on homework. he will interview a sample o

f 150 students. which method would result in a random sample from the population of students at salim's school?
Mathematics
1 answer:
Aloiza [94]2 years ago
8 0

Using sampling concepts, it is found that the method that would result in a random sample is given by:

Pick 150 students' names from a jar that has the names of all the students in the school.

<h3>How are samples classified?</h3>

Samples may be classified as:

  • Convenient: Drawn from a conveniently available pool.
  • Random: All the options into a hat and drawn some of them.
  • Systematic: Every kth element is taken.
  • Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
  • Stratified: Also divides the population into groups. Then, a equal proportion of each group is surveyed.

Researching the problem on the internet, the representative(all possible students can possibly be sampled) and random sample is given by the following option:

Pick 150 students' names from a jar that has the names of all the students in the school.

More can be learned about sampling concepts at brainly.com/question/25122507

#SPJ1

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In a scale model of a table, 1 centimeter represents 8 inches.
Trava [24]

Answer:

(a): 6 centimeters

(b): 72 inches

Step-by-step explanation:

Rule: From centimeters to inches, multiply centimeters × 8

so from inches to centimeters, divide inches by 8

Scale:

1 cm : 8 in

? cm : 48 in

6 cm : 48 in

Scale:

? in : 9 cm

72 in : 9 cm

8 0
3 years ago
According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var
-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

A)

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.7

10.9

11.2

11.5

11.8

n=10(even)

Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : \sqrt{\frac{\sum(x-\bar{x})^2}{n}}

Standard deviation :\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}

Standard deviation :0.89916

C)

8.3

,10.3

,10.5

,10.6

,10.7

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range :(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0
3 years ago
Z − 181 = –170<br> I need to solve for z please.
snow_tiger [21]

Answer:

z−181=−170

Step 1: Add 181 to both sides.

z−181+181= −170+181

z=11

5 0
2 years ago
In her shop lee had a piece of fabric measuring 150 meter a costumer asked her to sew 10 cushion covers each requiring 3 meters
maria [59]

Answer:

  99 m

Step-by-step explanation:

The 10 covers required ...

  (10 covers) × (3 m/cover) = 30 m

So the amount remaining is ...

  150 m - 30 m - 21 m = 99 m

Lee has 99 m of the fabric left.

6 0
3 years ago
at a certain time of day, a 40 foot building casts a 8 foot shadow. how tall is a person who casts a 2 foot shadow?
lions [1.4K]
40 feet = 8 foot shadow

So in order to go from 40 to 8 you divide by 5.
 So if you have a person who casts a 2 foot shadow, you have to multiply by 5.

Your answer would be 10 feet.
Hope I helped :)
7 0
3 years ago
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