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3 years ago

PLEASE HELP and explain how you got the answer!!

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

9514 1404 393

Answer:

256,096 ft²

Step-by-step explanation:

<u>Pyramid Area</u>

Each of the four faces is a triangle with a base of 756 feet and a height of 612 feet. The area of that triangle is ...

A = 1/2bh

A = 1/2(756 ft)(612 ft) = 231,336 ft²

The total area of the four visible faces of the Great Pyramid is ...

pyramid area = 4 × 231,336 ft² = 925,344 ft²

Each of the four rectangular side faces of the WTC tower has a base length of 208 ft and a height of 1368 ft. The area of it is ...

A = LW = (208 ft)(1368 ft) = 284,544 ft²

The area of the square top of the tower has an area that is ...

A = s² = (208 ft)² = 43,264 ft²

The total area of the four visible sides and the top is ...

WTC tower area = 4 × 284,544 ft² +43,264 ft² = 1,181,440 ft²

The difference between the areas is ...

WTC tower area - Great Pyramid area =

1,181,440 ft² -925,344 ft² = 256,096 ft²

The difference in visible area is 256,096 ft².

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Discount;
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3 years ago

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Answer:

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2 years ago

Help plz! loads of points!

babunello [35]

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3 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

Hey smart math people help me please

Ymorist [56]

Answer: First off thats not how you ask for help, by calling us "smart math people" that could offend someone...Second off the answer is 10 because

Step-by-step explanation:

A^2 + B^2 = C^2

6^2 + 8^2 = C^2

36 + 64 = 100 square root that = 10

Answer: 10

3 0

3 years ago

Read 2 more answers

*PLEASE HELP and explain how you got the answer!!*

PLEASE HELP and explain how you got the answer!!