Aluminum's outer electron in 3p-orbital is slightly further from the nucleus and protected by 3s-orbital. This causes it to need less energy. Magnesium's outer electron is closer and not protected by an outer orbital.
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Combustion:
The saturated hydrocarbons are relatively inert except at high temperatures. Combustion is one of the more important chemical reactions of the alkanes.
Alkanes have the general formula of CnH2n+2. For example, an alkane with 6 carbon atoms (n = 6) would have a formula of C6H2·6+2 or C6H14. Structurally C6H14 would be shown as:
Answer:
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Answer:</h3>
4.56 × 10^-19 Joules
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Explanation:</h3>
We are given;
- Wavelength of the wave as 435.8 nm
We are required to calculate the amount of energy released by an electron.
- We know that the speed of the wave, c is 2.998 × 10^8 m/s
- But, c = f × λ , where f is the frequency and λ is the wavelength
- Energy of a wave is given by the formula;
E = hf , where h is the plank's constant, 6.626 × 10^-34 J-s
But, f = c/λ
Therefore;
f = (2.998 × 10^8 m/s) ÷ (4.358 × 10^-7 m)
= 6.879 × 10^14 Hz
Thus;
Energy = 6.626 × 10^-34 J-s ×6.879 × 10^14 Hz
= 4.558 × 10^-19 Joules
= 4.56 × 10^-19 Joules
Therefore, the energy that must be released by the electron is 4.56 × 10^-19 Joules
