Sodium, hydrogen, carbon, and oxygen
Answer:
2.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 0.109 mole
Pressure (P) = 0.98 atm
Temperature (T) = 307 K
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
The volume of the helium gas can be obtained by using the ideal gas equation as follow:
PV = nRT
0.98 × V = 0.109 × 0.0821 × 307
0.98 × V = 2.7473123
Divide both side by 0.98
V = 2.7473123 / 0.98
V = 2.8 L
Thus, the volume of the helium gas is 2.8 L.
35 b.
37 h
39 i
41 d
hope that helps
The concentration of hydroxide ion is 5
10^
−
14 M.
<u>Explanation:</u>
Consider the equilibrium of this acid's dissociation,
H
C
l
O
4 ⇌ H
+ + C
l
O 4
-
Moreover, let's assume that H
C
l
O
4 is a strong acid and will fully dissociate.
Hence,
[
H
+
] = 0.20 M
Now, recall,
K
w = [
H
+
]
[
O
H
−
] = 1.0
10
^−
14
Hence,
⇒
[
O
H
−
] = K
w / [
H
+
] = 5
10^
−
14 M.