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WITCHER [35]
3 years ago
13

Need help asap with this chemistry if someone could help me

Chemistry
1 answer:
Burka [1]3 years ago
5 0

Answer:

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

Structure Number Two would likely be the most stable structure.

<h3>2)</h3>
  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

The N atom is the one that is "likely" to be attracted to an anion. See explanation.

Explanation:

When calculating the formal charge for an atom, the assumption is that electrons in a chemical bond are shared equally between the two bonding atoms. The formula for the formal charge of an atom can be written as:

\text{Formal Charge} \\ = \text{Number of Valence Electrons in Element} \\ \phantom{=}-\text{Number of Chemical Bonds} \\\phantom{=} - \text{Number of nonbonding Lone Pair Electrons}.

For example, for the N atom in structure one of the first question,

  • N is in IUPAC group 15. There are 15 - 10 = 5 valence electrons on N.
  • This N atom is connected to only 1 chemical bond.
  • There are three pairs, or 6 electrons that aren't in a chemical bond.

The formal charge of this N atom will be 5 - 1 - 6 = -2.

Apply this rule to the other atoms. Note that a double bond counts as two bonds while a triple bond counts as three.

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

In general, the formal charge on all atoms in a molecule or an ion shall be as close to zero as possible. That rules out Structure number one.

Additionally, if there is a negative charge on one of the atoms, that atom shall preferably be the most electronegative one in the entire molecule. O is more electronegative than N. Structure two will likely be favored over structure three.

<h3>2)</h3>

Similarly,

  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

Assuming that electrons in a chemical bond are shared equally (which is likely not the case,) the nitrogen atom in this molecule will carry a positive charge. By that assumption, it would attract an anion.

Note that in reality this assumption seldom holds. In this ion, the N-H bond is highly polarized such that the partial positive charge is mostly located on the H atom bonded to the N atom. This example shows how the formal charge assumption might give misleading information. However, for the sake of this particular problem, the N atom is the one that is "likely" to be attracted to an anion.

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<h2>Answer:</h2>

<u>A</u><u>.</u><u> </u><u>True</u><u> </u>

<h2>Explanation:</h2>
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