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WITCHER [35]
4 years ago
13

Need help asap with this chemistry if someone could help me

Chemistry
1 answer:
Burka [1]4 years ago
5 0

Answer:

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

Structure Number Two would likely be the most stable structure.

<h3>2)</h3>
  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

The N atom is the one that is "likely" to be attracted to an anion. See explanation.

Explanation:

When calculating the formal charge for an atom, the assumption is that electrons in a chemical bond are shared equally between the two bonding atoms. The formula for the formal charge of an atom can be written as:

\text{Formal Charge} \\ = \text{Number of Valence Electrons in Element} \\ \phantom{=}-\text{Number of Chemical Bonds} \\\phantom{=} - \text{Number of nonbonding Lone Pair Electrons}.

For example, for the N atom in structure one of the first question,

  • N is in IUPAC group 15. There are 15 - 10 = 5 valence electrons on N.
  • This N atom is connected to only 1 chemical bond.
  • There are three pairs, or 6 electrons that aren't in a chemical bond.

The formal charge of this N atom will be 5 - 1 - 6 = -2.

Apply this rule to the other atoms. Note that a double bond counts as two bonds while a triple bond counts as three.

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

In general, the formal charge on all atoms in a molecule or an ion shall be as close to zero as possible. That rules out Structure number one.

Additionally, if there is a negative charge on one of the atoms, that atom shall preferably be the most electronegative one in the entire molecule. O is more electronegative than N. Structure two will likely be favored over structure three.

<h3>2)</h3>

Similarly,

  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

Assuming that electrons in a chemical bond are shared equally (which is likely not the case,) the nitrogen atom in this molecule will carry a positive charge. By that assumption, it would attract an anion.

Note that in reality this assumption seldom holds. In this ion, the N-H bond is highly polarized such that the partial positive charge is mostly located on the H atom bonded to the N atom. This example shows how the formal charge assumption might give misleading information. However, for the sake of this particular problem, the N atom is the one that is "likely" to be attracted to an anion.

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sergeinik [125]

Answer : The formula for each of the following is:

(a) C_{22}H_{46}

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(c) C_{13}H_{24}

Explanation :

  • Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is C_n H_{2n+2} where n is the number of the carbon atoms present in a molecule of alkane.

  • Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is C_n H_{2n} where n is the number of the carbon atoms present in a molecule of alkene.

  • Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is C_n H_{2n-2} where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, C_{22}H_{2(22)+2} or C_{22}H_{46}

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, C_{17}H_{2(17)} or C_{17}H_{34}

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, C_{13}H_{2(13)-2} or C_{13}H_{24}

3 0
3 years ago
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tresset_1 [31]

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no

Explanation:

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How many quarters have the same value as 85 dimes? Use the equality 4 quarters = 10 dimes.?
marissa [1.9K]
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Help which one will it be
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What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?
yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃  +  3C  →  4Fe  +  3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

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0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

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