Which statement accurately depicts what happens to water on the molecular level in a tea pot when it begins to boil?

Chemistry

1 answer:

olga nikolaevna [1]3 years ago

8 0

Answer:

(a) The molecules begin to move farther apart decreasing their intermolecular forces and they escape the liquid state to enter the gas state.

Explanation:

As we put tea pot full of water on stove the heat transfer starts from surface of tea pot to the closest water molecule near the surface of tea pot, after becoming hot the water rises up and cooler water comes down. When water begins to boil their intermolecular forces begin to decrease and they start to convert in gaseous or vapor state.

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How many liters of CO2 gas can be produced at 30.0 °C and 1.50 atm from the reaction of 5.00 mol of C3H8 and an excess of O2 acc

lbvjy [14]

Answer:

249 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 5.00 moles of C₃H₈

The molar ratio of C₃H₈ to CO₂ is 1:3. The moles of CO₂ produced are 3/1 × 5.00 mol = 15.0 mol

Step 3: Convert "30.0°C" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 30.0°C + 273.15 = 303.2 K

Step 4: Calculate the volume of carbon dioxide

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 15.0 mol × 0.0821 atm.L/mol.K × 303.2 K/1.50 atm

V = 249 L

5 0

3 years ago

the formula of calcium oxide is CaO. What is the formula of the ionic compound containing calium abd sulfate ions

sineoko [7]

Answer:

$CaS$

Explanation:

Hello!

In this case, since calcium's oxidation state when forming ionic bonds is +2 and sulfur's oxidation state when bonding those bonds is -2, for the required formula we write:

$Ca^{2+}S^{2-}$

Now, since they have the same charge number, we infer the ionic compound formed when they bond is calcium sulfide:

$CaS$

Best regards!

5 0

2 years ago

D( )-Camphor is treated with 5-methoxytryptamine in the presence of sodium cyanoborohydride to generate a new molecule, as a sin

Svetach [21]

The reducing agent can approach the carbonyl face of camphor by forming a one carbon bridge (known as an exo attack) or a two carbon bridge (termed endo).

The two resultant stereoisomers are known as isoborneol and borneol (from exo attack) (from endo attack). Gas chromatography (GC) analysis may be used to calculate the ratio of each isomeric alcohol in the mixture. Unfortunately, IR analysis does not permit this.

The stereochemistry of the reaction is regulated in stiff cyclic compounds like camphor and norcamphor by protecting one side of the carbonyl group from the reagent's assault. The hydrogen atom is added to the endo side, creating the exo alcohol isoborneol, while the methyl groups on the one-carbon bridge of camphor screen the approach of the hydride from the "top" or exo side of the two-carbon bridge. You will be asked to guess the main isomeric alcohol created by the norcamphor hydride reduction later in the lab report.

To view more about rational reaction, refer to:

brainly.com/question/20308523

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