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2 years ago

A carbon-12 atom has 6 protons, 6 neutrons, and 6 electrons. How many protons does a carbon-14 atom have?

Chemistry

2 answers:

Anuta_ua [19.1K]2 years ago

5 0

Answer:

A carbon-14 atom has 6 protons, 8 neutrons and 6 electrons. The number 12 or 14 in the name of carbon-12 and carbon-14 refers to their atomic mass.

Explanation:

Those atoms that have the same "atomic number" but differente "atomic mass" (or atomic weight) are called isotopes.

Atomic number indicates the amount of electrons that an atom has, which matchs with the number of protons it has.

Atomic mass indicates the sum of protons and neutrons that an atom has.

Example with carbon-12:

carbon atomic number = 6 (find this information in a periodic table)

electrons= 6

protons= 6

carbon atomic mass = 12 (find this information in a periodic table)

neutrons= atomic mass - number of protons= 12-6 = 6 neutrons

Using the same analysis for carbon-14:

carbon atomic number = 6

electrons= 6

protons= 6

carbon atomic mass = 14

neutrons= atomic mass - number of protons = 14-6 = 8 neutrons

In this way, carbon-14 is an isotope of carbon-12 because carbon-14 has the same atomic number than carbono-12 but different atomic mass.

serious [3.7K]2 years ago

4 0

An isotope of carbon always has 6 protons - that is the part of the atom which shows it is carbon. If it had a different number of protons, it would be a different element altogether

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Hello! Here's the answer I was able to come up with:

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It is physically impossible for an atom to have more than 8 electrons in its valence layer, according to the Octet Rule.

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The dot diagram for each element represents the number of electrons each element will have in its outermost, or valence, shell. (2-8-8)

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3 years ago

A chemist combined 0.440 L of an unknown calcium solution with an excess of ammonium chromate. This resulted in the precipitatio

Rina8888 [55]

The concentration of the original calcium ions is 0.005 M

<h3>What is concentration?</h3>

The term concentration has to do with the amount of substance in solution. We know that the concentration can be measured in a lot of units such as mole/litre, grams per litre, percentage and so on.

As such we have the equation;

Ca^2+(aq) + (NH4)2CrO4(aq) --------> CaCrO4(s) + 2NH4^+(aq)

Number of moles of the precipitate = 346.7 * 10^-3 g/156 g/mol

= 0.0022 moles

Now;

1 mole of Ca^2+ produces 1 mole of CaCrO4 hence 0.0022 moles of CaCrO4 was produced by 0.0022 moles of CaCrO4.

Given that the volume of the solution is 0.440 L, the concentration of the solution is; 0.0022 moles/0.440 L

= 0.005 M

Learn more about molarity:brainly.com/question/8732513

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1 year ago

Which carbon compound is soft, slippery, a decent electricity conductor, and bonded in a way that forms planes?

Mashcka [7]

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2 years ago

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A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your

amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$

Also, when number of moles are equal in a solution then the formula will be as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

It is given that $M_{1}$ is 8.00 M, $V_{1}$ is 7.00 mL, and $M_{2}$ is 0.80 M.

Hence, calculate the value of $V_{2}$ using above formula as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

$8.00 M \times 7.00 mL = 0.80 M \times V_{2}$

$V_{2} = \frac{56 M. mL}{0.80 M}$

= 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

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algol13

Answer:

Explanation:

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