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dangina [55]
3 years ago
11

If 345.1 g of CO2 are placed in a vessel whose volume is 32.1 L at a temperature of 20.0oC, what will the pressure be? (R= 0.082

1 atm*L/mole*K)
Chemistry
1 answer:
Finger [1]3 years ago
7 0

Answer:

5.88atm

Explanation:

First, we obtain the number of mole of CO2 present in the vessel. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the question = 345.1g

Number of mole of CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 345.1/44

= 7.84moles

Now we can easily calculate the pressure by doing the following:

Data obtained from the question include:

V (volume) = 32.1 L

T (temperature) = 20°C = 20 + 273 = 293K

R (gas constant) = 0.0821atm*L/mole*K

n (number of mole) = 7.84moles

P (pressure) =?

We will be making use of the ideal gas equation PV = nRT to calculate the pressure

PV = nRT

P = nRT/V

P = 7.84 x 0.0821 x 293/32.1

P = 5.88atm

Therefore, the pressure is 5.88atm

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Answer: C. Convection currents in the asthenosphere.

Explanation: Most geologists think that the movement of Earth's plates is caused by convection currents in the asthenosphere.

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3 years ago
What is the IUPAC name of the following compound?
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Answer:

(d) 3,7-dimethyl-4-nonyne.

Explanation:

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3 years ago
C5H12 + 8O2 → 5CO2 + 6H2O<br><br> Calculate the energy change for the reaction:
KATRIN_1 [288]
C5H12 (l) + 8O2 (g) ----> 5CO2 (g) + 6H2O (l)
Delta H = -3505.8 kJ/mol

C (s) + O2 (g) -----> CO2 (g)
Delta H = -393.5 kJ/mol

H2 (g) + (1/2)O2 (g) ------> H2O (l)
Delta H = -286 kJ/mol

Possible answers:
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8 0
3 years ago
Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

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