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3 years ago

12

What step of the scientific method do we decide whether our hypothesis was correct or not

1 answer:

dlinn [17]3 years ago

4 0

Test Your Hypothesis by Doing an Experiment
Your experiment tests whether your prediction is accurate and thus your hypothesis is supported or not. It is important for your experiment to be a fair test.

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When a lithium atom forms an Li+ ion, the lithium atom

gizmo_the_mogwai [7]

4, loses an electron. a plus sign indicates an atom is losing an electron while a minus sign indicates an atom is gaining an electron
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3 years ago

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Why are 99.9% of metals (pure) way more expensive than 95% metals?

a_sh-v [17]

Answer:

A pure metal is any metal that has not been joined with any other metal

Explanation:

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3 years ago

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Which statement about electrons is not true?a. One electron state is a bonding orbital between nucleib. One electron state is an

NemiM [27]

Answer:

b. One electron state is an anti-bonding orbital, which results in an absence of electron density between atoms.

Explanation:

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4 years ago

Neon is an inner gas because it’s outer ____ is full of electrons.

Fynjy0 [20]

Answer:

Neon is an inner gas because it’s outer <u>__shell__</u> is full of electrons.

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3 years ago

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

<u>Answer:</u> The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

<u>Explanation:</u>

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0

3 years ago