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puteri [66]
3 years ago
12

What step of the scientific method do we decide whether our hypothesis was correct or not

Chemistry
1 answer:
dlinn [17]3 years ago
4 0
Test Your Hypothesis by Doing an Experiment
Your experiment tests whether your prediction is accurate and thus your hypothesis is supported or not. It is important for your experiment to be a fair test.
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A 10.00 mL sample of a 1.07 M solution of potassium hydrogen phthalate (KHP, formula mass = 204.22 g/mol) is diluted to 250.0 mL
ser-zykov [4K]

Answer:

[KHP] = 0.0428M

Explanation:

2 methods to calculate concentration after dilution

1. Use dilution equation

Molarity of concentrate (M₁) x Volume of Concentrate (V₁)

           =    Molarity of dilute (M₂) x Volume of dilute (V₂)

M₁ x V₁ = M₂ x V₂ => M₂ = M₁ x V₁ / V₂ = (1.07M)(10ml)/(250ml) = 0.0428M

2. Concentration Equation

moles KHPh = Molarity (M)  x  Volume (V) = 1.07M x 0.010L =0.0107 moles KHP

Concentration KHP = moles solute / volume of solution in Liters

= 0.0107 moles KHP / 0.25L = 0.0428M

8 0
3 years ago
The career area of chemistry which is involved in the manufacturing of products is:
andrew-mc [135]
Chemical Production is the answer
7 0
2 years ago
Read 2 more answers
plz help very many points so there better be an answer if u say i just need the points sorry i will report u.
Naily [24]

Answer:

1-C

2-A

3-F

4-B

5-D

6-E

Explanation:

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7 0
3 years ago
A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, w
Fed [463]

Answer:

Density = 8.92 g/cm³

Explanation:

Density shows the relation of the mass and volume of a determined object. We have this deffinition:

Density = mass / volume

First of all, we calcualte the volume of the block of copper metal, with the data given:

8.4 cm . 5.5 cm . 4.6 cm = 212.52 cm³

Now we replace at the density formula:

Density = 1896 g /212.52 cm³  = 8.92 g/cm³

7 0
3 years ago
A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
goblinko [34]

<u>Answer:</u> The molarity of KOH is 0.84 M.

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given

n_1=2\\M_1=1.50M\\V_1=25.2mL\\n_2=1\\M_2=?M\\V_2=90mL

Putting values in above equation, we get:

1\times 1.50\times 25.2=2\times M_2\times 90\\\\M_2=0.84M

Hence, the molarity of KOH is 0.84 M.

7 0
3 years ago
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