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2 years ago

Amines are basic functional groups and produce hydroxide in water. Can you write the reaction for butylamine in water

Chemistry

1 answer:

sdas [7]2 years ago

6 0

Answer:

stuff

Explanation:

it is kewl and it does stuff

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Which of the following is most likely to be found in a crystalline structure

aev [14]

The correct answer is letter D: Quartz.

5 0

4 years ago

1. How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?

quester [9]

Answer:

For 2. the answer is 15.0 mL

For other examples, you can solve by exact way as I have solved the 2nd example.

I have writen down all the balanced chemical reaction equation for examples 1, 3, 4, 5 for you. ( picture 2 )

Explanation:

Please see the step-by-step solution in the picture attached below.(picture 1)

Hope this answer can help you. Have a nice day!

6 0

3 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

Answer: The boiling point of solution is 100.53

Explanation:

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

6 0

3 years ago

What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm?

AlekseyPX

The new volume of a 250 Ml sample of gas at 300k and 1atm if heated to 350 k at 1 atm is 291.67 Ml

calculation

This is solved using the Charles law formula since the pressure is constant.

that is V1/T1 = V2/T2 where,

V1 =250 ml

T1=300 K

V2=?

T2= 350 k

by making V2 the subject of the formula by multiplying both side by T2

V2= T2V1/T1

V2= (350 K x 250 ml) / 300K =291.67 Ml

5 0

4 years ago

If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?

lyudmila [28]

The balanced reaction is:

Mg (s) + 2HCl (aq) --> MgCl 2 (aq) + H 2 (g)

We are given the amount hydrochloric acid to be used for the reaction. This will be the starting point of the calculation.

40.0 g HCl ( 1 mol HCl / 36.46 g HCl) (1 mol H2 / 2 mol HCl) (2.02 g H2 / 1 mol H2) = 1.11 g H2

8 0

3 years ago