Question

a 125g bar of aluminum at 22 degrees celsius. determine the final temperature of the aluminum, if the amount of energy applied is equal to 3600 calories. the specific heat of aluminum is .90 j/gc

Answer 1

Answer : The final temperature of the aluminum is, $155.9^oC$

Explanation :

Formula used :

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat = 3600 cal = 15062.4 J    (1 cal = 4.184 J)

m = mass of aluminum = 125 g

c = specific heat of aluminum = $0.90J/g^oC$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $22^oC$

Now put all the given values in the above formula, we get:

$15062.4J=125g\times 0.90J/g^oC\times (T_{final}-22)^oC$

$T_{final}=155.9^oC$

Thus, the final temperature of the aluminum is, $155.9^oC$