Answer : 0.25 M
explanation :
- Molarity is the number of moles of solute per liters of solvent.
- Molarity (M) = (n) / V (liter) = 2 / 8 = 0.25 M
The given question is incomplete. The complete question is:
The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:
A. 
B. 
C. 
D.
Answer: A.
: decreases
B.
: decreases
C.
: no change
D.
: increases
Explanation:
Entropy is defined as the randomness of the system.
Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.
In reaction
, as gaseous reactant is changed to solid product, entropy decreases.
In reaction
, as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.
In reaction
, as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.
In reaction
, as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.
answer: A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances or phases.
Answer:
a. Polar
b. Polar
c. Non-polar
d. Non-polar
Explanation:
a.
, hydronium cation contains a positive charge. Just as any other ion, it is polar, as it has a net charge.
b.
has the same shape as water. There are two lone pairs on sulfur atom which produce an overall dipole moment in this molecule, the bent structure is polar.
c.
is non-polar, as the central atom, phosphorus, doesn't contain any lone pairs, all the dipole moments cancel out: two dipole moments in the vertical plane, P-Cl, and three P-Cl dipoles in the horizontal plane within a trigonal bipyramidal shape.
d.
is non-polar, since it's a tetrahedral molecule with no lone pairs on carbon atom, all four C-F dipole moments cancel out to yield a net 0 dipole moment.