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kari74 [83]
2 years ago
7

Match the following

Chemistry
1 answer:
irina1246 [14]2 years ago
3 0

The order would be coefficient, law of conservation of mass, products, and reactants respectively.

<h3>Word matching</h3>

The number written in front of a chemical symbol in an equation is called a coefficient.

The total mass of a system being unchanged is known as the law of conservation of mass

The substances made in chemical reactions are called products.

The starting materials in chemical reactions are called reactants.

More on reactions can be found here: brainly.com/question/17434463

#SPJ1

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A 40.27 g sample of a substance is initially at 24.8 °c. after absorbing 2099 j of heat, the temperature of the substance is 148
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Q = mCΔT
Q is heat in joules, m is mass, C is specific heat, and delta T is change in temp

2099 J = (40.27g)(C)(148.5 - 24.8) = .421 J / gram K
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3 years ago
Texas ranks __________ among the states in the amount of hazardous waste generated, carbon dioxide emissions, and toxic chemical
Tcecarenko [31]
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3 years ago
P4+ __02_ P4010 <br> I need help ASAP
klasskru [66]

Answer:

P_4+5O_2\rightarrow P_4O_{10}

Explanation:

Hello!

In this case, when we want to balance chemical reactions such as in this case, the idea is to equal to number of atoms of each element at each side of the equation according to the lay of conservation of mass, just as shown below:

P_4+5O_2\rightarrow P_4O_{10}

Because we have four phosphorous and ten oxygen atoms at each side.

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8 0
3 years ago
Answer ASAP!!!
eduard

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3 years ago
A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon
Gekata [30.6K]

Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

n₂ = 0.683 moles of the gas are required

<em />

8 0
3 years ago
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