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Elden [556K]
2 years ago
10

How does the law of conservation of energy apply to the changes in potential and kinetic energy of a pencil as it falls to the f

loor?
Chemistry
1 answer:
antiseptic1488 [7]2 years ago
7 0

The changes in the energy law of conservation of energy is Potential energy is converted to kinetic energy. Kinetic energy is converted into potential energy.

<h3>What is the law of conservation of energy?</h3>

Law of conservation of energy says that energy can neither be created nor destroyed, it just transformed from one form to another.

The energies are kinetic, potential, mechanical, gravitational, electrical, etc.

Thus, the changes in the energy law of conservation of energy is Potential energy is converted to kinetic energy. Kinetic energy is converted into potential energy.

Learn more about law of conservation of energy

brainly.com/question/20971995

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What is a number bond.
GenaCL600 [577]

Explanation:

number bonds are pairs of numbers that can be added together to make another number e.g. 4 + 6 = 10. They are some of the most basic and most importantparts ofmaths for children to learn

3 0
2 years ago
1. A gas having the following composition is burnt under a boiler with 50% excess air.
jeka94

The composition of the stack gas are :

CH_4= 0.8713

C_3H_8 = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of CH_4 : 70% of 100 g = 70 g

Mass of C_3H_8 : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of CH_4 : \frac{70 g}{16.04 g/mol} = 4.3 mole

Number of moles of C_3H_8: \frac{15 g}{144.1 g/mol} = 0.10 mole

Mass of CO : \frac{15 g}{28.01 g/mol} = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of CH_4: \frac{4.3}{4.935} = 0.8713

Mole fraction of C_3H_8 : \frac{0.10}{4.935} = 0.0202

Mole fraction of CO : \frac{0.53}{4.935} = 0.107

Hence, composition of the stack gas are:

CH_4 = 0.8713

C_3H_8 = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

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8 0
3 years ago
Which atom gives up its electrons most easily?<br><br> THE ANSWER IS “Rb”
Sedbober [7]

Answer:

cesium

In particular, cesium (Cs) can give up its valence electron more easily than can lithium (Li). In fact, for the alkali metals (the elements in Group 1), the ease of giving up an electron varies as follows: Cs > Rb > K > Na > Li with Cs the most likely, and Li the least likely, to lose an electron

Explanation:

8 0
3 years ago
Read 2 more answers
Which of the following statements about the formation of a solution is true? A. An ionic compound cannot dissolve when a molecul
Assoli18 [71]
C. Dissolution is associated with heat change.
4 0
3 years ago
What mass of H2SO4 is contained in 60.00 mL of a 5.85 M solution of sulfuric acid
strojnjashka [21]

First, we have to calculate the number of moles of H2SO4 in the solution:

V=60 mL = 0.06 L

c=5.85 mol/L

n=V×c=0.06×5.85=0.351 mol

Then we need to find the molar mass of H2SO4:

2×Ar(H) + Ar(S) + 4×Ar(O) =

=2 + 32 + 64 = 98 g/mol

Finally, we need to find the mass of H2SO4:

m=0.351 × 98 = 34.398 g

5 0
3 years ago
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