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2 years ago

According to an energy pyramid model, which trophic level is expected have the largest biomass in land ecosystems ?

Chemistry

1 answer:

Deffense [45]2 years ago

5 0

Answer:

According to an energy pyramid model, Producer is expected have the largest biomass in land ecosystems

Explanation:

In a trophic level, the producers possess the largest biomass. With the increasing trophic level, the biomass reduces. Hence, the producers at the base have high biomass.

On terrestrial ecosystem, the producers are the plants and trees and hence the greatest biomass exists in the plants and trees.

Hence, in an energy pyramid model, Producer is expected have the largest biomass in land ecosystems

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he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c

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The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

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<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

$\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_{244^oC}$ = equilibrium constant at 244°C = $6.7M^{-1}s^{-1}$

$K_{324^oC}$ = equilibrium constant at 324°C = ?

$E_a$ = Activation energy = 71.0 kJ/mol = 71000 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature = $244^oC=[273+244]K=517K$

$T_2$ = final temperature = $324^oC=[273+324]K=597K$

Putting values in above equation, we get:

$\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}$

Hence, the rate constant at 324°C is $61.29M^{-1}s^{-1}$

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