Jdusjfbehsbdbegsuxbshsudnd
Answer:
It kind of is logical so my answer is yes
Answer:
D
Explanation:
D is the answer because 2 is needed to know
by putting to much current through it ?
Answer:
![M_{acid}=0.0444M](https://tex.z-dn.net/?f=M_%7Bacid%7D%3D0.0444M)
Explanation:
Hello,
In this case, for the given reaction:
![H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4](https://tex.z-dn.net/?f=H%20_2%20S%20O%20_4%20%2B%202%20N%20a%20O%20H%20%5Crightarrow%202%20_H%202%20O%20%2B%20N%20a%20_2%20S%20O_%204)
We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:
![2*n_{acid}=n_{base}](https://tex.z-dn.net/?f=2%2An_%7Bacid%7D%3Dn_%7Bbase%7D)
That in terms of concentrations and volumes we can compute the concentration of the acid solution:
![2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M](https://tex.z-dn.net/?f=2%2AM_%7Bacid%7DV_%7Bacid%7D%3DM_%7Bbase%7DV_%7Bbase%7D%5C%5C%5C%5CM_%7Bacid%7D%3D%5Cfrac%7BM_%7Bbase%7DV_%7Bbase%7D%7D%7B2%2AV_%7Bacid%7D%7D%3D%5Cfrac%7B0.697M%2A28.07mL%7D%7B2%2A220.1mL%7D%5C%5C%20%5C%5CM_%7Bacid%7D%3D0.0444M)
Best regards.