Answer:
Elastic modulus of steel = 202.27 GPa
Explanation:
given data
long = 110 mm = 0.11 m
cross section 22 mm = 0.022 m
load = 89,000 N
elongation = 0.10 mm = 1 × 
m
solution
we know that Elastic modulus is express as
Elastic modulus = 
................1
here stress is
Stress = 
.................2
Area = (0.022)²
and
Strain = 
.............3
so here put value in equation 1 we get
Elastic modulus = 
Elastic modulus of steel = 202.27 × 
Pa
Elastic modulus of steel = 202.27 GPa
Answer:
The correct response is "821.88". A further explanation is given below.
Explanation:
According to the question,
The largest amount unresolved after five years would have been:
= 
= 
= 
Now,
time (t) will be:
= 
= 
So, monthly payment will be:
= 
= 
= 
Answer:
Purchase cost= 87056
Bar module cost= 292725
Explanation:
solution is attached below
Answer:
Answer for the question:
"Show that for a linearly separable dataset, the maximum likelihood solution for the logisitic regression model is obtained by finding a weight vector w whose decision boundary wx.
"
is explained in the attachment.
Explanation:
Answer:
Multiplying impulse response by t ( option D )
Explanation:
We can obtain The impulse response of strength 1 considering a unit step response by Multiplying impulse response by t .
When we consider the Laplace Domain, and the relationship between unit step and impulse, we can deduce that the Impulse response will take the inverse Laplace transform of the function ( transfer ) . Hence Multiplying impulse response by t will be used .
