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Ronch [10]
2 years ago
5

Compare and contrast histosols and aridosols, the soils of bogs and peat marshes versus those of deserts and arid regions respec

t
Chemistry
1 answer:
Nat2105 [25]2 years ago
7 0

Answer:

The histosols of peat pogs are soils rich in organic material but poor in mineral nutrients, and are not fertile. Conversely, aridosols (desert soils) have an abundance of mineral nutrients but a dearth of organic matter and are also not fertile.

hope i help✨!

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HEY I NEED ALL ANSWERS RIGHT NOW IT'S MISSING AND MY TEACHER ARE GRADING THEM NOW YOU WILL BE MARKED BRAINIEST
emmainna [20.7K]

Molar mass of butane:-

  • 4(12)+10=58u

Moles of Butane:-

  • 100/58=1.7mol

#16

  • 2mols of Butane produce 8mol CO_2
  • 1mol of butane produces 4mol CO_2

Moles of CO_2

  • 4(1.7)=6.8mol

Mass of CO_2:-

  • 44(6.8)=299.2g

#17

  • 2mols of butane need 13mol O_2
  • 1mol of butane needs 6.5mol O_2

Moles of O_2

  • 6.5(1.7)=11.05mol

Mass of O_2

  • 11.05(32)=353.6g
7 0
2 years ago
You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th
ASHA 777 [7]

Answer: The correct option is (c). The total pressure doubles.

Solution:

Initially,  only 4 moles of oxygen gas were present in the flask.

p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

The new total pressure will be twice of initial total pressure.

7 0
3 years ago
The electrons in the outer shell of an atom are called:<br> outer<br> ionized<br> polar<br> valence
Marrrta [24]
Valence.

The electrons in the outer shell of an atom are called valence electrons. 

Valence electrons determine whether the an element is ready form compounds. These electrons can be gained, lost, or shared in the formation of compounds.
7 0
3 years ago
Drag and drop the terms into the correct locations to describe how the relationship between photosynthetic organisms and animals
g100num [7]

Answer:

Photosynthetic bacteria must take in <u>Carbon Dioxide</u> to live, and they release <u>Oxygen </u> . Animals must take <u>Oxygen </u> to live, and they release <u>Carbon Dioxide.</u>

Explanation:

Photosynthesis:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Carbon dioxide + water + energy →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture  by chloroplast.

Chemical equation:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

Photosynthetic bacteria perform same function as plants.  These bacteria contain light harvesting pigments absorb carbon dioxide and release oxygen.

While animals take oxygen and release carbon dioxide to live. This respiration process is opposite to the photosynthesis.

Glucose + oxygen → carbon dioxide + water + 38ATP

4 0
3 years ago
A compound was found to be soluble in water. It was also found that addition of acid to an aqueous solution of this compound res
gogolik [260]

Answer:

c. Cr

Explanation:

Cr^3+(aq) + CO_3^2-(aq) ------------> Cr_2CO_3(s)

The compound is containing CO_3^2- ion.

If acid reacts with it, CO_2 evolves.

H^+ + CO_3^2- ----------> H_2O + CO_2

therefore,  Cr would form a precipitate when added to an aqueous solution of this compound. Cr2CO3 is the precipitate.

3 0
3 years ago
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