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Ira Lisetskai [31]
3 years ago
9

If 4.88 grams of zn react with 5.03 grams of s8 to produce 6.02 grams of zns, what are the theoretical yield and percent yield o

f this reaction? be sure to show the work that you did to solve this problem. unbalanced equation: zn + s8 zns
Chemistry
1 answer:
nataly862011 [7]3 years ago
8 0
<span>Balance the equation
    8Zn + S8 -----> 8ZnS
    work out how much ZnS is possible if all of each reagent were to react. The reagent that produces the least product is the limiting reagent.
    moles Zn = mass / molar mass = 4.88 g / 65.38 g/mol = 0.07464 moles
  8 moles Zn reacts to form 8 moles ZnS
  Therefore moles ZnS possible = moles Zn = 0.07464 moles

    moles S8 = 5.03 g / 256.48 g/mol = 0.01961 mol
  1 mole S8 reacts to form 8 moles ZnS
  Therefore moles ZnS possible = 8 x moles S8 = 0.1569 mol

    The amount of Zn provided gives the least ZnS, therefore Zn is the limiting reagent.
    The theoretical yield is the maximum possible yield possible from the reagents provided. It is the amount of product that will form if all the limiting reagent reacts.
  So in this case 4.88 g Zn yields 0.07464 mol ZnS

    theoretical mass ZnS = molar mass x moles
  = 97.44 g/mol x 0.07464 mol
  = 7.27 g

    % yield = actual yield / theoretical yield x 100/1
  = 6.02 g / 7.27 g x 100/1
  = 82.8 %</span>
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The correct answer is A. The conservationist credited with founding the Wilderness Society is Bob Marshall.

Bob Marshall was an American forester, botanist, traveler, climber, writer and social activist who advocated the preservation of unspoiled wildlife.

 

He actively contributed to the development and adoption of environmental regulations prohibiting the construction of roads in vast federal specially protected natural areas. In 1935 he became one of the founders of the public environmental organization The Wilderness Society and its main sponsor.  

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alukav5142 [94]

Answer:

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3 years ago
Consider the reaction 2 S + 3 O2 → 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?
Ymorist [56]

Answer:

A/1.      10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

      80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

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State the guideline you can use to predict the formula of:
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We can predict formula of ionic compounds by:

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  • Alkali metal group I ions have +1 charges.
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4 0
1 year ago
Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with t
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Answer:

Close to the calculated endpoint of a titration - <u>Partially open</u>

At the beginning of a titration - <u>Completely open</u>

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Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

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