I think is 6.588579795x10^13 Kg because the equation is E=mc^2 and E is your Joules and c^2= 9x10^16 so m=(c^2)/E
Mercury and carbon two electrodes can't be used with an inactive or inert material.
<h3>What is an electrode?</h3>
The electrode is the element which is used to complete the electric circuit in welding. Some time electrode is connected with the positive terminal and sometimes with a negative terminal, it depends on the requirement of the welding process.
Inert electrode is an electrode that serves only as a source or sink for electrons without playing a chemical role in the electrode reaction. Precious metals, mercury, and carbon are typically used as inert electrodes.
Therefore, neither of the two electrodes can be used with an inactive or inert material.
Learn more about electrodes here:
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Answer:
V = 240.79 L
Explanation:
Given data:
Volume of butane = ?
Temperature = 293°C
Pressure = 10.934 Kpa
Mass of butane = 33.25 g
Solution:
Number of moles of butane:
Number of moles = mass/ molar mass
Number of moles = 33.25 g/ 58.12 g/mol
Number of mole s= 0.57 mol
Now we will convert the temperature and pressure units.
293 +273 = 566 K
Pressure = 10.934/101 = 0.11 atm
Volume of butane:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
V = nRT/P
V = 0.57 mol × 0.0821 atm.L/ mol.K ×566 K / 0.11 atm
V = 26.49 L/0.11
V = 240.79 L
<span>The molecular formula is 8(CH2O)= C8H16O8.</span>
True, as an atom has the same chemical properties as the first bulk element. Dalton’s Atomic Theory explains all :))
