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NARA [144]
2 years ago
12

A sample of 4.0 L of nitrogen, at 1.2 atmospheres, is transferred to a 12 L container.

Chemistry
1 answer:
pychu [463]2 years ago
8 0

Answer:

0.40 atm

Explanation:

P1V1 = P2V2

(1.2)(4.0) = P2(12)

P2 = 0.40 atm

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According to the Lewis model of acids and bases, amines behave as bases in water because __________. View Available Hint(s) Acco
lyudmila [28]

Answer: the unshared pair of electrons on the nitrogen can accept a proton

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

Amines have a general molecular formula of RNH_2 which has lone pair of electrons on nitrogen and thus is able to donate electrons to a lewis acid which is short of electrons. In other words nitrogen can accept a proton.

RNH_2+H^+\rightarrow RNH_3^+

7 0
2 years ago
A neutral atom has 8 electrons and 8 neutrons. Which of the following correctly represents the atom? A) carbon-16 B) oxygen-16 C
bija089 [108]

Answer:

D

Explanation:

Oxygen is the 8th element in the periodic table. This means that oxygen has 8 protons and 8 electrons. In order to get the number of neutrons you take the atomic weight in this case 15.9999~16 and you subtract it by the number of protons (16-8).

6 0
3 years ago
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Digiron [165]

Answer:

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Explanation:

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6 0
3 years ago
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
2 years ago
Basic substances have a gritty texture.
crimeas [40]
<h3>1.<u> Answer;</u></h3>

False

<h3><u>Explanation;</u></h3>

Bases have some of the following properties;

  • They have a bitter taste
  • They have a slimy, or soapy feel on fingers
  • Most bases react with acids and precipitate salts.
  • Strong bases may react violently with acids.
  • Bases turn red litmus paper blue

<h3>2. <u>Answer;</u></h3>

An acid

<h3><u>Explanation;</u></h3>
  • When acids are dissolved in water, the concentration of the acid decreases and it becomes dilute.
  • It dissociates in water to give H+ ions or hydrogen ions.
  • All acidic solutions contain more hydrogen ions than hydroxide ions, therefore when added to water it increases the concentration of H+ ions in water, as water is a neutral substance whose concentration of H+ ions is equal to OH-.
5 0
2 years ago
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