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Answer:
Hydraulic press is called an instrument for multiplication of force. Why? Because it uses Pascal's idea and principle: F=p*S. If we apply small force to small piston you will generate a pressure. According to Pascal's law pressure is the same everywhere in closed system so the same pressure will act on large piston on the other side too.
Explanation:
Answer:
Explanation:
The velocity of the vehicle would increase because the the tanks (when filled with water) must have exerted a force which would reduce the velocity of the vehicle at a certain pressure on the gas pedal. Note that force equals mass multiplied by acceleration; as the mass decreases, so the force decreases. Thus, when the mass exerted by this tanks (on the vehicle) decrease as a result of the hole punctured in them, the force exerted by the tanks would also decrease causing an increase in velocity of the pick up truck when the same pressure is applied on the gas pedal throughout (before and after the puncture).
The conservation law that applied here is the law of conservation of energy which states that energy can neither be created nor destroyed but can be transformed from one form to another. This is because the energy the vehicle used in carrying the load (the tanks) was transformed to the energy that resulted in increasing it's velocity (no new energy was formed as the pressure on the gas pedal remained the same).
Answer:
(a) α = 35.20 rad/s^2
(b) θ = 802°
(c) v = 139.73 cm/s
(d) a = 156.64 cm/s^2
Explanation:
(a) To find the angular acceleration of the disc you use the following formula:
(1)
w: angular speed of the disc = 31.4 rad/s
wo: initial angular speed = 0 rad/s
t: time = 0.892s
You replace the values of the parameters in the equation (1):

The angular acceleration of the disc, for the given time, is 35.20rad/s^2
(b) To calculate the angle describe by the disc in such a time you use:
(2)

In degrees you have:

The angle described by the disc is 802°
(c) To calculate the tangential speed of the microbe for t=0.892s, you use the following formula:
(3)
w: angular speed for t = 0.892s = 31.4rad/s
r: radius of the disc = 4.45cm

The tangential speed is 139.73 cm/s
(d) The tangential acceleration is calculated by using the following formula:

α: angular acceleration for t=0.892s

The tangential acceleration is 156.64cm/s^2
Answer:
Work = 165670.4 J = 165.67 KJ
Explanation:
First, we will find the deceleration of the car, using the 3rd equation of motion:

where,
a = deceleration = ?
s = skid distance = 40 m
vf = final speed = 0 m/s
vi = initial speed = 17.2 m/s
Therefore,

the negative sign indicates deceleration here.
Now, we will calculate the braking force applied by the brakes on the car:

the negative sign indicates braking force.
Now, we will calculate the work done using the magnitude of this force:

<u>Work = 165670.4 J = 165.67 KJ</u>