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Leona [35]
3 years ago
9

How do I find the net force=mass• acceleration with 9kg and 3 acceleration??

Physics
2 answers:
Irina-Kira [14]3 years ago
8 0

== Take the formula (net force) = (mass) · (acceleration)

== Erase the word "mass".  Write "9 kg" in the space.

== Erase the word "acceleration".  Write "9 m/s² " in the space.

== Do the multiplication indicated by the " · " in the formula.

== The result of the multiplication is " = " or "equal to" the net force.

sashaice [31]3 years ago
7 0
Mass = weight × acceleration
=9×3
=27 Newtow
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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally
amid [387]

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

v^{2} - u^{2} = 2as

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

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6 0
2 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f
Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

u = 0m/s

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

s = ut+\frac{1}{2} at^2

Replacing,

1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2

u =6.4013m/s

The height of the acorn above the meter stick can be calculated as,

v^2 = u^2 +2gh

h = \frac{v^2-u^2}{2g}

h = \frac{6.4013^2-0^2}{2(9.8)}

h = 2.0906m

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

h = 2.0906+1.87

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4 0
3 years ago
Confidence intervals for the population mean μ and population proportion p _____ as the size of the sample increases.
Masja [62]

Answer:

becomes narrower

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Confidence intervals for the population mean μ and population proportion p becomes narrower as the size of the sample increases.

As,the sample size increases,standard error decreases,so margin of error decreases and hence width of CI decreases.

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3 years ago
Calculate the resistance 50 feet of awg no. 12 solid copper wire round to nearest 0. 01 ohms.
emmasim [6.3K]

The resistance of the conductor is 0.07940 Ohms.

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The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.

and it is formulated as:  

R=p\frac{l}{s}

where,

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Thus the resistance can be calculated as

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Korolek [52]

Answer:

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hope this helped!

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