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Leona [35]
3 years ago
9

How do I find the net force=mass• acceleration with 9kg and 3 acceleration??

Physics
2 answers:
Irina-Kira [14]3 years ago
8 0

== Take the formula (net force) = (mass) · (acceleration)

== Erase the word "mass".  Write "9 kg" in the space.

== Erase the word "acceleration".  Write "9 m/s² " in the space.

== Do the multiplication indicated by the " · " in the formula.

== The result of the multiplication is " = " or "equal to" the net force.

sashaice [31]3 years ago
7 0
Mass = weight × acceleration
=9×3
=27 Newtow
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Fan object moves in uniform circular motion in a circle of radius R=200 meters, and the objectes 5.00 seconds to
Leviafan [203]

Answer:

The centripetal acceleration of the object is 31550.72\ m/s^2.  

Explanation:

We have,

Radius of a circular path is 200 m

It takes 5 seconds to complete 10 revolutions. The angular velocity of the object is given by the rate of change of angular displacement per unit time :

\omega=\dfrac{\Delta \theta}{\Delta t}\\\\\omega=\dfrac{2\pi \times 10}{5}\\\\\omega=12.56\ rad/s

The centripetal acceleration of the object is given by :

a=\omega^2 r\\\\a=(12.56)^2 \times 200\\\\a=31550.72\ m/s^2

So, the centripetal acceleration of the object is 31550.72\ m/s^2.

6 0
3 years ago
The type of function that describes the amplitude of damped oscillatory motion is _______. The type of function that describes t
Salsk061 [2.6K]

Answer:

exponential

Explanation:

type of function that describes the amplitude of damped oscillatory motion is exponential because as we know that here function is

y = A × e^{\frac{-bt}{2m}}  × cos(ωt + ∅ )    ..................................... ( 1 )          

here function A × e^{\frac{-bt}{2m}}   is amplitude

as per equation ( 1 )it is exponential

so that we can say that amplitude of damped oscillatory motion is exponential

8 0
3 years ago
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olasank [31]
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2 years ago
How many moles of MgCl2 are there in 329 g of the compound?<br><br> Your Answer:
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Answer:3.46

Explanation:

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6 0
3 years ago
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Paladinen [302]

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7 0
3 years ago
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