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Leona [35]
3 years ago
9

How do I find the net force=mass• acceleration with 9kg and 3 acceleration??

Physics
2 answers:
Irina-Kira [14]3 years ago
8 0

== Take the formula (net force) = (mass) · (acceleration)

== Erase the word "mass".  Write "9 kg" in the space.

== Erase the word "acceleration".  Write "9 m/s² " in the space.

== Do the multiplication indicated by the " · " in the formula.

== The result of the multiplication is " = " or "equal to" the net force.

sashaice [31]3 years ago
7 0
Mass = weight × acceleration
=9×3
=27 Newtow
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If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the sa
My name is Ann [436]
You can compare the velocity of the car, 60 mph, with the velocity that a mass would acquire when falls from certain height.

First, convert 60 mph to m/s:

60 miles/h * 1.60 km/mile * 1000 m/km * 1h/3600s = 26.67 m/s

Second, calculate from what height a body in free fall reachs 26.67 m/s velocity when hits the floor.

free fall => Vf^2 = 2g*H => H = Vf^2 / (2g)

H = (26.67m/s)^2 / (2*9.8 m/s) = 36.2 m

If you consider that the height between the floors of a building is approximately 3.6 m, you get 36.2 m / 3.6 m/floor = 10 floors.

Then, you conclude that the force of impact is the same as driving you vehicle off a 10 story building.
7 0
3 years ago
Focus groups are one of the most widely used ________ methods to gain greater understanding of a current problem or to develop p
Zigmanuir [339]

Answer:

Exploratory

Explanation:

<u>Focus groups</u>

It is a small group of 8-12 respondents guided by a moderator through a thorough debate on a specific subject or idea.It's great for generation of ideas, brainstorming, insight into motives, attitudes, and perceptions. it can  show likes, dislikes,emotional requirements and prejudices.

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8 0
3 years ago
An aluminum wire having a cross-sectional area equal to 3.90 10-6 m2 carries a current of 6.00 A. The density of aluminum is 2.7
stich3 [128]

Answer:

Vd = 1.597 ×10⁻⁴ m/s

Explanation:

Given: A = 3.90×10⁻⁶ m², I = 6.00 A, ρ = 2.70 g/cm³

To find:

Drift Velocity Vd=?

Solution:

the formula is Vd = I/nqA         (n is the number of charge per unit volume)

n = No. of electron in a mole ( Avogadro's No.) / Volume

Volume = Molar mass / density   ( molar mass of Al =27 g)

V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³

n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)

n= 6.02 × 10 ²⁸

Now

Vd = (6A) / (  6.02 × 10 ²⁸ ×  1.6 × 10⁻¹⁹ C ×  3.9×10⁻⁶ m²)

Vd = 1.597 ×10⁻⁴ m/s

6 0
3 years ago
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gogolik [260]

Answer:

melting polar icecaps seems the best, hopes this helps!

6 0
3 years ago
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stiks02 [169]

Answer:

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P = 4500 J / min * .15 = 675 J / min

4 0
2 years ago
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