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jenyasd209 [6]
3 years ago
5

How does charging by conduction occur?

Physics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer : (A) A charged object is brought near a neutral object without touching it.

Explanation:

Bodies can be charged by the method of conduction. By conduction the body acquires the same charge as on the charging body.

Charging the body can be understood by the following example of charging a paper cylinder by conduction. Make a paper cylinder by rolling a strip of paper on a pencil and then gently pulling out the pencil. Suspend the paper cylinder by a string tied to its center, now touch the paper cylinder with a glass rod rubbed with silk so it has a positive charge. Remove the class rod and the again bring it near to the paper cylinder.

The paper cylinder is repelled by the positively charged rod. And when you bring a negatively rubbed rod, next to the cylinder it will be attracted towards the rod. This means that the paper cylinder has acquired a positive charge as on the glass rod due to conduction.

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What is the angular displacement of the second hand on a clock after 59 seconds?
DerKrebs [107]

Answer:

a. -6.17 rad

Explanation:

60 seconds is 2π radians.  Writing a proportion:

2π / 60 = x / 59

x = 6.17

The displacement is negative because the second hand moves clockwise.

6 0
3 years ago
Read 2 more answers
If two equal charges are separated by a certain distance, the force of repulsion is F. Given F1, if each charge in F1 is doubled
Alisiya [41]

Answer:F_2=16\times F_1

Explanation:

Given

Force of repulsion between two charge particle is given by force F

Electrostatic force is given by

F=\frac{kq_1q_2}{r^2}

where q_1 and q_2 is the charges  of particle

r=distance between charge particle

=\frac{kq^2}{r^2}when charges are doubled and distance is reduced to half

i.e. q become 2 q and r becomes 0.5 r

F_2=\frac{k(2q)^2}{(0.5r)^2}

F_2=\frac{kq^2}{r^2}\times 4\times 4

F_2=16\times F_1

         

6 0
3 years ago
Change of 5000 c flows through a circuit in one hour. what is the current intensity?​
AleksandrR [38]

Answer:

I = 1.38 A

Explanation:

Given that,

Charge, q = 5000 C

Time, t = 1 hour = 3600 s

We need to find the current intensity. The current intensity is equal to the electric charge per unit time. It can be given by :

I=\dfrac{q}{t}

Substitute all the values in the above formula

I=\dfrac{5000\ C}{3600\ s}\\\\=1.38\ A

So, the current intensity is 1.38 A.

8 0
3 years ago
If you climb to the top of Mt. Everest, you will be 8850 m (about 5.50 mi) above sea level.
Umnica [9.8K]

Answer:

9.773m/s2

Explanation:

Given,

h=8848m

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So,

Let g′ be the acceleration due to the gravity on the Mount Everest.

g′=g(1−h2h)

=9.8(1−640000017696)

=9.8(1−0.00276)

9.8×0.99724

=9.773m/s2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s2

Hope it helped!!!

5 0
3 years ago
On a hot summer day several swimmers decide to jump into a river. They step off the bridge and strike the water at 1.5s later. I
xxTIMURxx [149]
That is right  because base*length is how you get the height


6 0
3 years ago
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