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Montano1993 [528]
3 years ago
9

Four of your friends are in new relationships, but only two of these relationships are healthy. Which of your friends are in unh

ealthy relationships that have escalated to a safety risk? Take a look at the chart below to determine the answer: Jessica's partner says/does Kristen's partner says/does Shane's partner says/does Jack's partner says/does Jokes about Jessica's taste in music Prefers to make decisions and plans Asks, "What do you want to do tonight?" Wants Jack to cancel family time to go on a date Does not like Jessica gong out on the weekend Likes to discuss feelings and concerns together Laughs often at mutual jokes Yells to get Jack's attention Says, "Why do you make me so angry sometimes?" Wants to socialize with Kristen's brother and friends Shares new ideas and likes to be right all the time Pushes Jack jokingly Who is in an unhealthy relationship?
Physics
2 answers:
Ne4ueva [31]3 years ago
7 0
Jack and Jessica are in unhealthy relationships
svet-max [94.6K]3 years ago
5 0
Jack and Jessica are unhealthy 

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Calculate the average power required to lift a 750 N object a vertical distance of 10 meters in 4.0 seconds.
Nina [5.8K]

Answer:

500

Explanation:

5 0
2 years ago
A 6 kg box with initial speed 5 m/s slides across the floor and comes to a stop after 1.9 s. What is the coefficient of kinetic
Ilia_Sergeevich [38]

Answer:

\mu_k=0.27

Explanation:

According to the free body diagram, in this case, we have:

\sum F_x:-F_k=ma\\\sum F_y:N=mg

Recall that the force of friction is given by:

F_k=\mu_k N

Replacing and solving for the coefficient of kinetic friction:

-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}

We have an uniformly accelerated motion. Thus, the acceleration is defined as:

a=\frac{v_f-v_0}{t}\\a=\frac{0-5\frac{m}{s}}{1.9s}\\a=-2.63\frac{m}{s^2}

Finally, we calculate \mu_k:

\mu_k=-\frac{-2.63\frac{m}{s^2}}{9.8\frac{m}{s^2}}\\\mu_k=0.27

4 0
3 years ago
Give Example of mental flexibility
Inessa [10]

Answer:

If you ring the doorbell and no one opens the door, you'll infer that no one is home rather than continuing to ring the doorbell to an empty house. Being able to understand this and look for another solution is another example of mental flexibility.

Explanation:

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2 years ago
Essential Questions: What does the particle theory tell us about the nature of matter? How does
Ede4ka [16]

sowwie :( i need points

Explanation:

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2 years ago
At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is
n200080 [17]

a) 8.93\cdot 10^{-30} N, downward

b) 1.76\cdot 10^{-17} N, upward

c) 1.20\cdot 10^{-17} N, downward

Explanation:

a)

The gravitational force of an object (also known as weight of the object) is the attractive force with which the object is pulled towards the Earth's centre.

For an object near the Earth's surface, the magnitude of the gravitational force is given by the equation

F=mg

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

m=9.11\cdot 10^{-31} kg is the mass of the electron

g=9.8 m/s^2 is the acceleration due to gravity

Therefore, the gravitational force on the electron is:

F=(9.11\cdot 10^{-31})(9.8)=8.93\cdot 10^{-30} N

And the direction is downward, towards the Earth's centre.

b)

The electric force on a charged particle is the force produced by the presence of an electric field.

In particular, this force is:

- Repulsive (away from the source of the field) if the charge has the same sign of the charge source of the field

- Attractive (towards the source of the field) if the charge has opposite sign to the charge source of the field

The magnitude of the electric force is given by:

F=qE

where

q is the charge of the particle

E is the strength of the electric field

In this problem:

q=1.6\cdot 10^{-19} C is the charge of the electron

E=110 N/C is the strength of the electric field

Substituting,

F=(1.6\cdot 10^{-19})(110)=1.76\cdot 10^{-17} N

And since the electron has negative charge, the  direction of the force is opposite to that of the electric field, so upward.

c)

When a charged particle is moving in a magnetic field, it experiences a force which is perpendicular to both the direction of motion of the charge and to the direction of the magnetic field.

The magnitude of this force is given by (if the charge moves perpendicular to the magnetic field)

F=qvB

where

q is the charge

v is the velocity of the particle

B is the strength of the magnetic field

In this problem:

q=1.6\cdot 10^{-19} C is the charge of the electron

v=1.50\cdot 10^6 m/s is the velocity

B=50.0\mu T = 50.0 \cdot 10^{-6} T is the strength of the magnetic field

Substituting,

F=(1.6\cdot 10^{-19})(1.50\cdot 10^6)(50.0\cdot 10^{-6})=1.20\cdot 10^{-17} N

And the direction can be determined using the right-hand rule:

- Index finger: direction of velocity (eastward)

- Middle finger: direction of magnetic field (northward)

- Thumb: direction of force (upward) --> however the electron has negative charge, so the direction of the force is reversed --> downward

5 0
2 years ago
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