1) X-component: 568.5 N, Y-component: 511.9 N
2) The horizontal force is 86.6 N and the resulting acceleration is
Explanation:
1)
In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.
The two components are given by:
where
F = 765 N is the magnitude of the force
is the angle of the force with the horizontal
Substituting, we find:
- Horizontal component:
- Vertical component:
2)
First of all, we have to find the horizontal component of the pulling force, which is given by
where
F = 100 N is the magnitude of the pulling force
is the direction of the force with the horizontal
Substituting,
Now we can find the acceleration of the wagon by using Newton's second law:
where
is the net force in the horizontal direction
m = 100 kg is the mass of the wagon
is the acceleration in the horizontal direction
Solving for , we find
Learn more about vector components:
And about Newton's second law:
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