KE=(1/2)mv^2
KE=(1/2)(600 kg) (12 m/s) ^2
KE=(1/2)(600 kg) )144 m^2/s^2)
KE= 43,200 kg*m^2/s^2=43,200 Joules
Answer:
Approximately 
to the right (assuming that both astronauts were originally stationary.)
Explanation:
If an object of mass 
is moving at a velocity of 
, the momentum 
of that object would be 
.
Since momentum of this system (of the astronauts) conserved:
.
Assuming that both astronauts were originally stationary. The total initial momentum of the two astronauts would be 
since the velocity of both astronauts was 
.
Therefore:
.
The final momentum of the first astronaut (
, 
to the left) would be 
to the left.
Let 
denote the momentum of the astronaut in question. The total final momentum of the two astronauts, combined, would be 
.
.
Hence, 
. In other words, the final momentum of the astronaut in question is the opposite of that of the first astronaut. Since momentum is a vector quantity, the momentum of the two astronauts magnitude (
) but opposite in direction (to the right versus to the left.)
Rearrange the equation to obtain an expression for velocity in terms of momentum and mass: 
.
.
Hence, the velocity of the astronaut in question (
) would be to the right.
Answer:
B
Explanation:
When the sun, moon, and Earth are in alignment at the time of the new or full moon, the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides both commonly called spring tides.
On the Newtonian theory of gravity, gravitation affects anything with mass. Assuming that none of the answer choices is the only thing that exists in the universe, all of the answer choices are subject to the law of universal gravitation (hence “universal”).
Satellites, water, frogs, and stars all have mass as they are all composed of matter. Thus, all four answer choices should be circled.
