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kaheart [24]
3 years ago
11

What is the direction of the net force that acts on an object undergoing uniform circular motion?

Physics
2 answers:
krok68 [10]3 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

An object moves with a constant speed when it has uniform circular motion. Due to change in direction this object accelerates.

Therefore, net force acts towards the center of circle which is also said to be inward force or centripetal force.

Thus, we can conclude that direction of the force is toward the center of the object's circular path that acts on an object undergoing uniform circular motion.



8_murik_8 [283]3 years ago
5 0
D. The direction of the force is toward the center of the object's circular path.
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The crew of an enemy spacecraft attempts to escape from your spacecraft by moving away from you at 0.259 of the speed of light.
Vladimir79 [104]
If you do not have to use relative physics but classic physics, this is how you solve it:

Speed of light = c = 3 * 10^5 km/s

Speed of your foe respect to you: 0.259c

Speed of the torpedo respect to you: 0.349c

Speed of the torpedo respect your foe: 0.349c - 0.259c = 0.09c

Conversion to km/s = 0.09 * 3.0 * 10^5 km/s = 27000 km/s

Note that this solution, using classic physics do not take into account time and space dilation.

Answer: 27000 km/s
4 0
3 years ago
4. A chandelier brightens a ballroom after a waiter moves a switch
Leokris [45]

Answer:

because switch moves after a waiter

Explanation:

7 0
3 years ago
What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.0 km/h and the co
bazaltina [42]

Answer:

Explanation:

Let the radius of track required be r.

Centripetal force will be provided by frictional force which will be equal to

m v²/ r

Frictional force = mg x μ

So

m v² /r = mg μ

r = v² / μ g =

  v = 29 km /h = 8.05 m /s

r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m

5 0
3 years ago
Part A
geniusboy [140]

Answer:

a) b = -5

b) slope = 3/2

Explanation:

a) The equation of a line is given as y = mx + b, where m is the slope of the line and b is the intercept on the y axis.

Given that y = 3x + b and it passes through the point (2, 1). Hence when x = 2, y = 1. Therefore, substituting for x and y:

1 = 3(2) + b

1 = 6 + b

b = 1 - 6

b = -5

b) The equation of a line passing through two points (x_1,y_1) and x_2,y_2 is given by:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of the line passing through the two points (0,3) and (4,9) is:

y-3=\frac{9-3}{4-0}(x-0)\\ \\y-3=\frac{3}{2}x\\ \\y = \frac{3}{2}x+3

Comparing y = (3/2)x + 3 with y = mx + b, the slope (m) is 3/2

4 0
2 years ago
A ball is dropped from the roof of a 25-m-tall building. What is the velocity of the object when it touches the ground? Suppose
Wewaii [24]

Answer:

a)  h=25m

b)  v=19.8m/sec

Explanation:

From the question we are told that:

Height h=25m

Bounce Height h'=20m

Generally the Kinematic equation is mathematically given by

V=\sqrt{2gh}\\\\V=\sqrt{2*9.81*25}

V=22.1m/sec

Therefore Height

h=\frac{V^2}{2g}\\\\h=\frac{22.1^2}{2*9.81}

h=25m

b)

Generally the Kinematic equation is mathematically given by

v^2=2ah

v^2=2*9.8*20

v=\sqrt{2*9.8*20}

v=19.8m/sec

3 0
3 years ago
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