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3 years ago

9

What is drag? In what situations might it act on the force of gravity?

2 answers:

stepan [7]3 years ago

7 0

Drag is passive, therefore it does not act on gravity. Drag is a mechanical resistance to motion. If the motion in question was induced by gravity drag it can impede that motion, but has no effect on the gravity.

hope this helps!

WITCHER [35]3 years ago

6 0

Answer:

Drag is a force of resistance that acts in fluid motion. When there is relative motion with respect to a fluid, a drag force acts in the opposite direction to the motion. Drag depends on viscosity, compressibility of the fluid and mass of the object.

When the sum of drag force and buoyant force are equal to the downward force of gravity, the object falls with a constant velocity known as terminal velocity.

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Answer: 0.790 g/cm3

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b) $11.60\cdot 10^{-3} J$

c) $8.33\cdot 10^{-3} J$

Explanation:

a)

The energy stored in a capacitor is given by

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For the capacitor in this problem, before insering the dielectric, we have:

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b)

After the dielectric is inserted into the plates, the capacitance of the capacitor changes according to:

$C'=kC$

where

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Therefore, the energy stored now in the capacitor is:

$U'=\frac{1}{2}C'V^2=\frac{1}{2}kCV^2$

where:

$C=13.5\cdot 10^{-6}F$ is the initial capacitance

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Substituting, we find:

$U'=\frac{1}{2}(3.55)(13.5\cdot 10^{-6})(22.0)^2=11.60\cdot 10^{-3} J$

C)

The initial energy stored in the capacitor, before the dielectric is inserted, is

$U=3.27\cdot 10^{-3} J$

The final energy stored in the capacitor, after the dielectric is inserted, is

$U'=11.60\cdot 10^{-3} J$

Therefore, the change in energy of the capacitor during the insertion is:

$\Delta U=11.60\cdot 10^{-3}-3.27\cdot 10^{-3}=8.33\cdot 10^{-3} J$

So, the energy of the capacitor has increased by $8.33\cdot 10^{-3} J$

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