a sample of sulfur dioxide occupies a volume of 652 mL at 40.0 C and 0.75 atm. What volume will the sulfur dioxide occupy at STP
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Balanced chemical equation is 3CH₃CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃COOH + 4Cr³⁺ + 11H₂O.
<h3>What is Balanced Chemical Equation ?</h3>The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The chemical equation
CH₃CH₂OH + Cr₂O₇²⁻ → CH₃COOH + Cr³⁺
First assign the oxidation number for each atom in the equation.
Oxidation: C₂H₆O → C₂H₄O₂ + 4e⁻
Reduction: Cr₂O₇ + 6e⁻ → 2Cr⁺³
Now, balance the charge
Oxidation: C₂H₆O → C₂H₄O₂ + 4e⁻ + 4H⁺
Reduction: Cr₂O₇ + 6e⁻ + 14H⁺ → 2Cr⁺³
Now balance the oxygen atoms
Oxidation: C₂H₆O + H₂O → C₂H₄O₂ + 4e⁻ + 4H⁺
Reduction: Cr₂O₇ + 6e⁻ + 14H⁺ → 2Cr⁺³ + 7H₂O
Now, make electron gain equivalent to lost
Oxidation: C₂H₆O + H₂O → C₂H₄O₂ + 4e⁻ + 4H⁺ } × 3
Reduction: Cr₂O₇ + 6e⁻ + 14H⁺ → 2Cr⁺³ + 7H₂O } × 2
Now,
Oxidation: 3C₂H₆O + 3H₂O → 3C₂H₄O₂ + 12e⁻ + 12H⁺
Reduction: 2Cr₂O₇ + 12e⁻ + 28H⁺ → 4Cr⁺³ + 14H₂O
Now, add the both equations
3CH₃CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃COOH + 4Cr³⁺ + 11H₂O
Thus from the above conclusion we can say that the balanced chemical equation is 3CH₃CH₂OH + 2Cr₂O₇²⁻ + 16H⁺ → 3CH₃COOH + 4Cr³⁺ + 11H₂O.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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