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RoseWind [281]
2 years ago
8

a sample of sulfur dioxide occupies a volume of 652 mL at 40.0 C and 0.75 atm. What volume will the sulfur dioxide occupy at STP

?
Chemistry
1 answer:
sesenic [268]2 years ago
5 0

The volume that sulfur dioxide will occupy with a volume of 652 mL at 40.0°C and 0.75 atm is 0.019moles. Details about volume can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the following formula:

PV = nRT

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

0.75 × 0.652 = n × 0.0821 × 313

0.489 = 25.69n

n = 0.489/25.69

n = 0.019moles

Therefore, the volume that sulfur dioxide will occupy with a volume of 652 mL at 40.0°C and 0.75 atm is 0.019moles.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

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There are two naturally occurring isotopes of indium: indium-113 and indium-115. How many neutrons are in a single atom of indiu
KonstantinChe [14]
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2 years ago
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6 0
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Lead (ll) nitride+ammonium sulfate &gt; lead(ll) sulfate + ammonium nitride
Alenkinab [10]

Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

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2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

4. Ammonium nitride would require three amonium cations to balance the nitride anion: (NH_4)_3N.

Let's write the balanced equation:

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7 0
3 years ago
When 0.105 mol propane, C3H8 is burned in an excess of oxygen, how many moles of oxygen are consumed? The products are carbon di
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<u>Answer:</u> The amount of oxygen gas consumed is 0.525 moles

<u>Explanation:</u>

We are given:

Moles of propane burned = 0.150 moles

The chemical equation for the combustion of propane follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction:

1 mole of propane reacts with 5 moles of oxygen gas

So, 0.150 moles of propane will react with = \frac{5}{1}\times 0.105=0.525mol of oxygen gas

Hence, the amount of oxygen gas consumed is 0.525 moles

6 0
3 years ago
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