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Svetlanka [38]
3 years ago
15

The Dome of the Rock and Al-Aqsa Mosque are located in what city?

Chemistry
2 answers:
horrorfan [7]3 years ago
7 0

Old City of Jerusalem

Nataly_w [17]3 years ago
5 0
They are located in Jerusalem.
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50 POINTS PLEASE HELP!
Aleks04 [339]

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

Rate = \frac{1}{\sqrt{M}}

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\

where,

M_{1} = molar mass of hydrogen gas

M_{2} = molar mass of another given gas

R_{1} = rate of diffusion of hydrogen

R_{2} = rate of diffusion of another given gas = \frac{1}{7}R_{1}

Substitute the values into above formula as follows.

\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} =  \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

7 0
3 years ago
Read 2 more answers
If 6. 000 g of sugar is mixed with 9. 000 g of water, what is the concentration in weight percent?.
lbvjy [14]

The concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

There are several ways to denote the concentration of a solution like

  • Molarity
  • Molality
  • Mass percent
  • Mole Fraction

The formula for calculating mass percent is as follows

Mass per cent = (Mass of solute/Mass of solute + Mass of solvent) x 100%

In the given situation sugar is the solute and water is the solvent.

Putting the given values in the above formula

Mass per cent = (6/6+9) x 100%= 6/15 x 100% = 40%

Hence, the concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

To know more about "concentration of a solution", refer to the link given below:

brainly.com/question/26579666?referrer=searchResults

#SPJ4

7 0
1 year ago
Consider the reaction below that has a Keq of 8.98 X 10-2. The initial concentration of A and B is 1.68 M. Calculate the equilib
DaniilM [7]

Answer:

[C] = 0.4248M

Explanation:

                   A     +     B      ⇄     2C

C(i)          1.68M      1.68M         0.00

ΔC              -x            -x             +2x

C(eq)      1.68-x       1.68-x          2x

Keq = [C]²/[A][B] = (2x)²/(1.68 - x)²= 8.98 x 10⁻²

Take SqrRt of both sides => √(2x)²/(1.68 - x)² = √8.98 x 10⁻²

=> 2x/1.68 - x = 0.2895

=> 2x = 0.2895(1.68 - x)

=> 2x = 0.4863 - 0.2895x

=> 2x + 0.2895x = 0.4863

=> 2.2895x = 0.4863

=> x = 0.4863/2.2895 = 0.2124

[C] = 2x = 2(0.2124)M = 0.4248M in 'C'

3 0
3 years ago
Read 2 more answers
8. Electrons are located in the nucleus of an atom. *
r-ruslan [8.4K]

Answer:

8- False

9- False

10-atomic number

6 0
3 years ago
The sulfate ion is an example of a(n) __________ because it contains two different elements.
myrzilka [38]

it is an example of a compound

5 0
3 years ago
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