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Cloud [144]
3 years ago
7

Can you make a love potion

Chemistry
2 answers:
OlgaM077 [116]3 years ago
8 0
I am pretty sure you can't, but hey everything is possible! :)
yaroslaw [1]3 years ago
3 0
No unless u mix science potions together to make a love potion
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10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters
kipiarov [429]

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of sodium carbonate = 10.6 g

Volume of water = 1.25 L

Molarity of solution = ?

Solution:

First of all we will calculate the moles of solute.

Number of moles = mass/molar mass

Number of moles = 10.6 g/ 106 g/mol

Number of moles = 0.1 mol

Formula:

Molarity = moles of solute / volume of solution in L

Now we will put the values in formula.

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M

4 0
3 years ago
Consider the following equilibrium systems: A⇌2B ΔH o =20.0 kJ/mol Reaction 1 A+B⇌C ΔH o =−5.4 kJ/mol Reaction 2 A⇌B ΔH o =0.0 k
galina1969 [7]

Answer:

Reaction 1: Kc increases

Reaction 2: Kc decreases

Reaction 3: The is no change

Explanation:

Let us consider the following reactions:

Reaction 1: A ⇌ 2B ΔH° = 20.0 kJ/mol

Reaction 2: A + B ⇌ C ΔH° = −5.4 kJ/mol

Reaction 3: 2A⇌ B ΔH° = 0.0 kJ/mol

To predict what will happen when the temperature is raised we need to take into account Le Chatelier Principle: when a system at equilibrium suffers a perturbation, it will shift its equilibrium to counteract such perturbation. This means that <em>if the temperature is raised (perturbation), the system will react to lower the temperature.</em>

Reaction 1 is endothermic (ΔH° > 0). If the temperature is raised the system will favor the forward reaction to absorb heat and lower the temperature, thus increasing the value of Kc.

Reaction 2 is exothermic (ΔH° < 0). If the temperature is raised the system will favor the reverse reaction to absorb heat and lower the temperature, thus decreasing the value of Kc.

Reaction 3 is not endothermic nor exothermic (ΔH° = 0) so an increase in the temperature will have no effect on the equilibrium.

8 0
3 years ago
If 1.20 moles of an ideal gas occupy a volume of 18.2 l at a pressure of 1.80 atm, what is the temperature of the gas, in degree
scoundrel [369]

We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚<span>C</span>

6 0
3 years ago
A pH change can be evidence that​
drek231 [11]

Answer:

Explanation:

The acid level has changed

3 0
3 years ago
Which of these is the final result of secondadry succession?
Grace [21]

Answer:

a

Explanation:

ADAPTATIOnn but if thhere would be an option o all the above it would be that

5 0
3 years ago
Read 2 more answers
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