Answer:
A. How much decay happens in each flashlight
Explanation:
In an experiment, the DEPENDENT OR RESPONDING VARIABLE is the variable that responds to changes being made to another variable called Independent variable. It is the variable that is measured by an experimenter.
In this question, an experiment was carried out to research the effect of sunlight on plastic decay. Three plastic flashlights were used for this experiment in which one was placed in a dark closet (control), and the others were placed in light at different times or intervals. However, the variable being measured or assessed is the decay of each flashlight. This means that "HOW MUCH DECAY HAPPENS IN EACH FLASHLIGHT" is the dependent variable.
Answer: The answer is C. A mercury thermometer is better to measure very small changes in temperature.
Explanation:
i took this quiz and this is the answer .
A) A mercury thermometer can measure the freezing point of a liquid that freezes at −80 °C.
B) An alcohol thermometer can measure the boiling point of a liquid that boils at 80 °C.
C) A mercury thermometer is better to measure very small changes in temperature.
D) An alcohol thermometer is better to measure the boiling points of colorless liquids.
Answer: sulphur is an element with RAm of 32g/mol
Saturated solution is the solution which do not dissolve more soulute at given temperature
Answer:
Human land use impacts the environment by causing certain events which can lead to more serious events such as climate change, poor air and water quality, and environmental degradation.
One example is when humans clear out space such as forests (deforestation). This leads to habitat loss which lowers the population of certain species affecting biodiversity thus impacting the environment.
Explanation:
Since, we have the reaction as,
2Li(s) + F2(g) --> 2LiF(s)
we are only concerned with the limiting reactants. We calculate for the amount of product that can be produced with the given amount of reactants.
a. 1 g Li(1 mol / 6.941 g of Li)(2 mol LiF/2 mol Li) = 0.144 mol LiF2
1 g F2(1 mol/38 g)(2 mol LiF2/1 mol F2) = 0.052 mol LiF2
Answer: 1 g of F2
b. 10.5 g Li(1 mol/6.941 g of Li)(2 mol LiF/2 mol Li) = 1.512 mol LiF2
37.2 g F2(1 mol/38 g)(2 mol LiF2/1 mol F2) = 1.958 mol LiF2
Answer: 10.5 g of Li
c. (2.85 x 10^3 g Li)(1 mol/6.941 g of Li)(2 mol LiF/2 mol Li) = 410.60 mol LiF2
(6.79 x 10^3 g F2)(1 mol/38 g)(2 mol LiF2/1 mol F2) = 357.368 mol of LiF2
Answer: 6.79 x 10^3 g F2