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Vesnalui [34]
2 years ago
15

Compared to a soft sound, a loud sound at the same pitch....(check all true statements)

Physics
1 answer:
Sladkaya [172]2 years ago
3 0

Answer:

One might think of a plucked guitar string - the sound would depend on the original amplitude of the disturbance -

Speed and velocity would still be the same

(b) is correct because the energy transfer depends on the original energy applied.

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a 3 kg piece of putty that is moving with a velocity of 10 m/s collides and sticks to an 8 kg bowling ball that was at rest. wha
defon

The final velocity is 2.7 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the system must be conserved before and after the collision.

Therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 3 kg is the mass of the putty

u_1 = 10 m/s is the initial velocity of the putty (we take its direction as positive direction)

m_2 = 8 kg is the mass of the ball

u_2 = 0 m/s is the initial velocity of the ball (at rest)

v is the final combined velocity of the two putty+ball

Re-arranging the equation and substituting the values, we find the  final combined velocity:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(3)(10)+0}{3+8}=2.7 m/s

And the positive sign indicates their final direction is the same as the initial direction of the putty.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

3 0
3 years ago
Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1.0 mm.
pantera1 [17]

Answer:

R_a/R_b=3

Explanation:

The resistance in terms of the area and the length of the wire is given by:

R=pL/A

if we have two wires, the first one is a solid wire with a diameter of d_A = 1 x 10^-3 m, and the second one is a hollow wire with inner diameter of d_B,i = 1 x 10^-3 m and outer diameter of d_B,σ= 2 x 10^-3 m, so the cross sectional area of the first wire is:  

A_a=πr^2_a

A_a=πd^2_A/4

hence the resistance is:  

R_a=(4*p*L_a)/π*d^2_A                                     (1)

the area of the second wire is:  

A_b=π*r^2_B,σ-π*r^2_B,i

A_b=π/4(d^2_B,σ-d^2_B,i)

hence the resistance is:  

R_b=(4*p*L_b)/π(d^2_B,σ-d^2_B,i)                   (2)

To find the ratio between the resistances R_a/R_b, we divide (1) over (2) to get:  

R_a/R_b=(d^2_B,σ-d^2_B,i)*L_a/(d^2_a*L_b)

but the wires have the same length, therefore:  

R_a/R_b=(d^2_B,σ-d^2_B,i)/(d^2_a)

substitute with the given values to get:

R_a/R_b=3

6 0
3 years ago
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Please help me with this
Firlakuza [10]

Answer:

can't see anything sorry can't help

7 0
3 years ago
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The Bohr model of the atom suggest that the protons and neutrons are found in the nucleus and the electrons orbit the nucleus mu
Tanzania [10]

Answer:

I think it is D

Explanation:

the Bohr model says that electrons whizz around the atomic nucleus in the same way that the earth goes around the sun - but rather than being bound by gravity, it is bound by electromagnetic forces.

8 0
4 years ago
HELP FOR POINTS PLEASE
alukav5142 [94]

Explanation:

a wind breaker .......

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