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4 years ago

It takes less time to manually move patients than to use lift equipment. Is this statement a myth or fact?

Physics

2 answers:

sergejj [24]4 years ago

7 0

Fact. Using lift equipment would take longer.

9966 [12]4 years ago

6 0

Answer:

Fact

Explanation:

Lift equipments may be far away places. And to bring the lift eqiupment near to the patients may take much longer time because he lift equipment may be engaged with some other patient or may not be available. Thus it is more reliable and faster to move the patient manually to the destination than using a lift which will take longer time.

Thus it is a FACT.

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Explain with one example that different types of organisums live in one habitation

inn [45]

Answer:

When you look at a simple koi pond you can find Koi (the secondary consumer) that feeds off of the zooplankton (first consumer), they eat the phytoplankton (producers). All in a simple food chain

Explanation:

Basically, Koi eat the little animal plankton (zooplankton) that then eats the plant plankton (phytoplankton) that can only end when a part of that habitat is removed. If you got rid of the plant plankton then the whole chain would collapse and most likely die.

5 0

3 years ago

Energy may be measured in?

hram777 [196]

Answer:

Energy May be measured in joule

6 0

3 years ago

Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 m

alexandr1967 [171]

Answer:

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm = $0.407\times 10^{-3}\ m$

Energy stored in the capacitor (U) = $7.87\ nJ=7.87\times 10^{-9}\ J$

Assuming the medium to be air.

So, permittivity of space (ε) = $8.854\times 10^{-12}\ F/m$

Area of the square plates is given as:

$A=a^2=(0.0419\ m)^2=1.75561\times 10^{-3}\ m^2$

Capacitance of the capacitor is given as:

$C=\dfrac{\epsilon A}{d}\\\\C=\frac{8.854\times 10^{-12}\ F/m\times 1.75561\times 10^{-3}\ m^2 }{0.407\times 10^{-3}\ m}\\\\C=3.819\times 10^{-11}\ F$

Now, we know that, the energy stored in a parallel plate capacitor is given as:

$U=\frac{CE^2d^2}{2}$

Rewriting in terms of 'E', we get:

$E=\sqrt{\frac{2U}{Cd^2}}$

Now, plug in the given values and solve for 'E'. This gives,

$E=\sqrt{\frac{2\times 7.87\times 10^{-9}\ J}{3.819\times 10^{-11}\ F\times (0.407\times 10^{-3})^2\ m^2}}\\\\E=49880.77\ N/C$

Therefore, the electric field strength inside the capacitor is 49880.77 N/C

8 0

3 years ago

What happens when magnesium reacts with fluorine

slamgirl [31]

It creates a white crystal salt MgF2

3 0

3 years ago

A simple pendulum having a length of 1.02 m and a mass of 6.66 kg undergoes simple harmonic motion when given an initial speed o

attashe74 [19]

Answer:

Time period of pendulum is 2.02 s.

Explanation:

A simple pendulum is a device which consists of mass m hanging from the string of length L attached to the some point.When displaced and released its swings back and forth with periodic motion.

The time period of pendulum is defined as time taken by the pendulum to complete one full oscillation . it is denoted by T.

By Huygens law of period of pendulum,

T = 2π $\sqrt{\frac{L}{g} }$ eqn 1

where L is the length of pendulum,

g is acceleration due to gravity

Period of pendulum is independent of the mass of pendulum,

Substituting values in eqn 1

T = 2π $\sqrt{\frac{1.02}{9.8\\} }$

T = 2.02 s

Time period of pendulum is 2.02 s.

4 0

3 years ago