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4 years ago

It takes less time to manually move patients than to use lift equipment. Is this statement a myth or fact?

Physics

2 answers:

sergejj [24]4 years ago

7 0

Fact. Using lift equipment would take longer.

9966 [12]4 years ago

6 0

Answer:

Fact

Explanation:

Lift equipments may be far away places. And to bring the lift eqiupment near to the patients may take much longer time because he lift equipment may be engaged with some other patient or may not be available. Thus it is more reliable and faster to move the patient manually to the destination than using a lift which will take longer time.

Thus it is a FACT.

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A 80 kg parent and a 20 kg child meet at the center of an ice rink. They place their hands together and push. The parent pushes

Ymorist [56]

Answer:

force acting on the parent = 25 N .

Explanation:

According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .

Answer is 25 N .

4 0

3 years ago

A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the

Vesna [10]

So, based on the angle values that have been found, the angle of elevation of the nozzle can be <u>16° or 74°</u>.

<h3>Introduction</h3>

Hi ! This question can be solved using the principle of parabolic motion. Remember ! When the object is moving parabolic, the object has two points, namely the highest point (where the resultant velocity is 0 m/s in a very short time) and the farthest point (has the resultant velocity equal to the initial velocity). At the farthest distance, the object will move with the following equation :

$\boxed{\sf{\bold{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}}}$

With the following condition :

$\sf{x_{max}}$ = the farthest distance of the parabolic movement (m)
$\sf{v_0}$ = initial speed (m/s)
$\sf{\theta}$ = elevation angle (°)
g = acceleration due to gravity (m/s²)

<h3>Problem Solving :</h3>

We know that :

$\sf{x_{max}}$ = the farthest distance of the parabolic movement = 2.5 m
$\sf{v_0}$ = initial speed = 6.8 m/s
g = acceleration due to gravity = 9.8 m/s²

<h3>What was asked :</h3>

$\sf{\theta}$ = elevation angle = ... °

Step by Step :

Find the equation value $\sf{\bold{theta}}$ (elevation angle)

$\sf{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}$

$\sf{x_{max} \cdot g = (v_0)^2 \cdot \sin(2 \theta)}$

$\sf{\frac{x_{max} \cdot g}{(v_0)^2} = \sin(2 \theta)}$

$\sf{\frac{2.5 \cdot 9.8}{(6.8)^2} = \sin(2 \theta)}$

$\sf{\frac{24.5}{46.24} = \sin(2 \theta)}$

$\sf{\sin(2 \theta) \approx 0.53}$

$\sf{\cancel{\sin}(2 \theta) \approx \cancel{\sin}(32^o)}$

Find the angle value of the equation by using trigonometric equations. Provided that the parabolic motion has an angle of elevation 0° ≤ x ≤ 90°.

First Probability

$\sf{2 \theta = 32^o + k \cdot 360^o}$

$\sf{\theta = 16^o + k \cdot 180^o}$

→ $\sf{k = 0 \rightarrow 16^o + 0 = 16^o}$ (T)

→ $\sf{k = 1 \rightarrow 16^o + 180^o = 196^o}$ (F)

Second Probability

$\sf{2 \theta = (180^o - 32^o) + k \cdot 360^o}$

$\sf{2 \theta = 148^o + k \cdot 360^o}$

$\sf{\theta = 74^o + k \cdot 180^o}$

→ $\sf{k = 0 \rightarrow 74^o + 0 = 74^o}$ (T)

→ $\sf{k = 1 \rightarrow 74^o + 180^o = 254^o}$ (F)

$\boxed{\sf{\therefore \theta \{16^o , 74^o\} }}$

<h3>Conclusion</h3>

So, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.

8 0

3 years ago

State the condition under which a satellite would move with escape velocity

elixir [45]

When the launch velocity is a bit less than the escape velocity, the satellite with time will find itself back to earth and when the speed is far beyond the escape velocity, the satellite with time, be lost in space.

The velocity of escape from the less massive Moon is about 2.4 km per second at its surface. ... A planet (or satellite) cannot long retain an atmosphere if the planet's escape velocity is low enough to be near the average velocity of the gas molecules making up the atmosphere.

7 0

3 years ago

What is the outermost structure in a plant cell

dybincka [34]

Molecular structure of the primary cell wall in plants. Up to three strata or layers may be found in plant cell walls: The middle lamella, a layer rich in pectins. This outermost layer forms the interface between adjacent plant cells and glues them together.

5 0

3 years ago

A pendulum is timed, first for 20 swings and then for

wlad13 [49]

$w = \frac{t(50) - t(20)}{50 - 20} = \frac{43.2 - 17.4}{50 - 20}$

$w = \frac{25.8}{30} = 0.86 \: sec \: per \: swing$

The results may differ due to resistive forces that may be affecting the system by decelerating it or any other external forces that might accelerate it a bit.Or the timing could be a little inaccurate.

3 0

2 years ago