So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2
The answer would be true so you would know which way it was going and how fast it was moving towards you
x = 3 t² - 2 t + 3
When t=2 sec, x = 3 (4) - 2 (2) + 3
= 12 - 4 + 3 = 11 meters .
When t=3 sec, x = 3 (9) - 2 (3) + 3
= 27 - 6 + 3 = 24 meters .
Distance = (end position) - (start position) = (24m - 11m) = 13 meters
Time = (end time) - (start time) = (3s - 2s) = 1 second
Speed = (distance) / (time) = 13 meters / 1 sec = 13 meters/second
<h2><em>is used for the large-scale generation of electricity</em></h2>
- <em>Large scale power generation includes existing technology and infrastructure used to provide electricity in the UK. Current facilities use predominantly fossil fuel based technologies, such as </em><em><u>coal and gas</u></em>
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