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fredd [130]
3 years ago
13

Calculate the velocity of a 1650 kilogram satellite.

Physics
1 answer:
Anna35 [415]3 years ago
8 0

There's not enough information given to do that calculation.

-- The question doesn't specify whether the satellite is on the
shelf in the Vehicle Assembly Building before being installed
onto the booster, or inside the nose-cone as the rocket is slowly
being rolled to the launch-pad, or on its ascent to orbit after launch,
or in orbit.  Its velocity in each of these situations is different.

-- The question reveals only the satellite's mass, but the answer
doesn't depend on that number.  The satellite's velocity depends
on the speed of the truck or the rocket carrying it, or the size of
the orbit it's in.  The question doesn't give any of these.

==> In particular, the size of a satellite's orbit, or its speed in that
orbit, DO NOT depend on its mass.

For example: 
There are hundreds of TV satellites ... the ones that match the
Earth's rotation and appear motionless in the sky.  They have
many different sizes, shapes, and masses, but they're all in the
same geostationary orbit, 22,000 miles above the equator, and
they all have the same average orbital velocity, zero displacement
per (23 hours 56 minutes 4 seconds).

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3 years ago
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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

Where,

F_D = Drag Force

c_D = Drag coefficient

A = Area

\rho= Density

V = Velocity

Our values are given by,

c_D = 0.5 (That is proper of a cone-shape)

A = 9m^2

\rho = 1.2Kg/m^3

V = 6.5m/s

Part A ) Replacing our values,

F_D = 0.5*9*\frac{1.2*6.5^2}{2}

F_D = 114.075N

Part B ) To find the torque we apply the equation as follow,

\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
A little girl kicks a soccer ball, it goes 10 feet then comes back to her, how is this possible??
kirza4 [7]
Its gravitational force

7 0
3 years ago
pls help quick. the number line shows the starting and ending velocities for ball 1 what's the change in velocity of ball 1 calc
pentagon [3]

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

7 0
3 years ago
In a television set, electrons are accelerated from rest through a potential difference of 20 kV. The electrons then pass throug
Svetradugi [14.3K]

Answer: Fmax = 5.54*10^-12 N

Explanation: From the question, we have the potential difference (V) =20kv = 20,000v and strength of magnetic field (B) =0.41 T.

The maximum force experienced by a charge of magnitude (q) is given as

Fmax = qvB

Where v = velocity of electron.

The velocity of the electron can be gotten by using the work energy theorem.

The kinetic energy of the electron (mv²/2) equals the work done needed to accelerate it.

mv²/2 = qV.

Where m = mass of an electronic charge = 9.11×10^-31 kg, q = magnitude of an electronic charge = 1.609×10^-19 c, v = velocity of electron, V = potential difference = 20,000v.

By substituting the parameters, we have that

(9.11×10^-31 × v²)/2 = 1.609×10^-19 × 20000

(9.11×10^-31 × v²) = 1.609×10^-19 × 20000 ×2

v² = (1.609×10^-19 × 20000 ×2)/9.11×10^-31

v² = 64.36*10^(-16)/9.11×10^-31

v² = 7.0647×10^15

v = √7.0647×10^15

v = 8.40×10^7 m/s

Fmax = 1.609×10^-19 × 8.40×10^7 × 0.41

Fmax = 5.54*10^-12 N

7 0
3 years ago
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