Calculate the velocity of a 1650 kilogram satellite.
1 answer:
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Answer:
2.13 x 10^-19 J or 0.53 eV
Explanation:
cut off wavelength, λo = 700 nm = 700 x 10^-9 m
λ = 400 nm = 400 x 10^-9 m
Use the energy equation
Where, K be the work function
K = 2.13 x 10^-19 J
K = 0.53 eV
Answer:
a) 24.33 m of distance.
b) 34.55° east of the south.
Explanation:
The question is incomplete. The whole exercise is the following:
<em>"Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different directions. Ricardo walks 28.0 m in a direction 60.0° west of north. Jane walks 12.0 m in a direction 30.0° south of west. They then stop and turn to face each other. </em>
<em>(a) What is the distance between them? </em>
<em>(b) In what direction should Ricardo walk to go directly toward Jane?</em><em>"</em>
Now that we know what we need to do in this question, let's head for every part of the problem.
<u>a) Distance between Ricardo and Jane</u>
In this case, we need to analyze the given data:
Ricardo (which we will call R) is 28 m from the starting point at 60° west of north, and Jane (J) is 12 m at 30° south of west. So the distance between them, will be the point where they both stop and face each other. This point can be seen in the image attached (See picture).
Let's call the distance between them as "D", to get the distance of D, according to the picture will be:
D = J - R (1)
However, as they are facing in different angles and directions, we cannot do the difference of their values distance just like that. In order to do that, we need to calculate the components in the "x" and "y" axis of each vector. In that way, we can get the components of x and y of the Distance D, and then, the whole distance between them will be:
D = √Dx² + Dy² (2)
So, let's get the components of x and y of R and J.
For Ricardo (R):
Rx = R sin60° = 28 sin60° = -24.25 m
Ry = R cos60° = 28 cos60° = 14 m
The sign "-" it's because R it's on the second quadrant, therefore in x, we'll have to add the negative.
For Jane (J):
Jx = J cos30° = 12 cos30° = -10.39 m
Jy = J sin30° = 12 sin30° = -6 m
Again, the negative is added because J is on the third quadrant.
Now that we have the components, let's calculate vector D using expression (1):
Dx = -10.39 - (-24.25) = 13.86 m
Dy = -6 - 14 = -20 m
Now, using expression (2) we can finally know the distance between Jane And Ricardo:
D = √(-20)² + (13.86)²
<h2>D = 24.33 m</h2>This is the distance between Jane and Ricardo.
b) Direction of Ricardo walking to Jane
In this case, we already have the components of x and y of the distance between them, so, to know the direction:
Tanα = Dy/Dx
α = tan⁻¹ (Dy/Dx)
Replacing the values we have:
α = tan⁻¹ (-20/13.86)
α = 55.45°
Which should south of east or:
β = 90 - 55.45
<h2>β = 34.55°</h2>Ricardo should walk 34.55° east of south
Hope this helps
a) the number of protons is more than the electrons
b)
Explanation:
The net electric charge on the ball is
This electric charge is given by the algebraic sum of the charge of the protons and of the charge of the electrons.
The charge of one proton is:
While the charge of one electron is
So the net charge on the metal ball will be given by
where
is the number of protons
is the number of electrons
So we find:
This means that the number of protons is more than the electrons.
b)
In this case, we want to make the ball neautral, so we have to remove a net charge of Q' such that the new charge is zero:
This implies that the charge that we must remove is
To do that (and to make the ball losing mass at the same time), we have to remove protons, since they have positive charge.
The number of protons that must be removed is:
The mass of one proton is
Therefore, the total mass that must be removed from the ball is